LeetCode(2) Add Two Numbers
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简单的两个链表数值合并的操作,需要注意的就是极端样例。
# Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = Noneclass Solution: def fuse(self,l1,l2,is_carry=0): if l1 is None and l2 is None: if is_carry == 0: return None else: return ListNode(is_carry) res = ListNode(0) if l1 is None: l1 = ListNode(0) elif l2 is None: l2 = ListNode(0) res.val = l1.val + l2.val + is_carry is_carry=0 if res.val>9: is_carry = 1 res.val = res.val % 10 res.next = self.fuse(l1.next,l2.next,is_carry) return res def addTwoNumbers(self, l1, l2): """ :type l1: ListNode :type l2: ListNode :rtype: ListNode """ ori = self.fuse(l1,l2,0) res = [] while True: if ori is None: return res else: res.append(ori.val) ori = ori.next return res
下附一些极端样例
[],[]
[1],[9,9,9,9,9,9]
[2],[8,9,8]
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