Sqlplus,设置 不换行,列宽,隐藏标题

来源:互联网 发布:周小平扒皮网络大v 编辑:程序博客网 时间:2024/06/11 13:03
set heading off,隐藏列标题set line 1000,设置行长度col XXX format a40(XXX为列名称,根据实际情况调整a40这个值),设置列宽
SQL*Plus: Release 11.2.0.3.0 Production on Wed Dec 13 10:03:55 2017Copyright (c) 1982, 2011, Oracle.  All rights reserved.Connected to:Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit ProductionWith the Partitioning, OLAP, Data Mining and Real Application Testing optionsSQL>  SELECT SEGMENT_NAME AS TABLE_NAME,  2          SUM(BYTES) / (1024 * 1024 * 1024) "TABLE_SIZE[GB]"  3     FROM DBA_SEGMENTS T  4    WHERE T.SEGMENT_NAME = 'BUSTB_TESTRESULT'  5      AND SEGMENT_TYPE = 'TABLE SUBPARTITION'  6      AND PARTITION_NAME LIKE 'RESULT_PART_201301%'  7    GROUP BY SEGMENT_NAME;TABLE_NAME--------------------------------------------------------------------------------TABLE_SIZE[GB]--------------BUSTB_TESTRESULT    8.19140625SQL> set wrap off;SQL>  SELECT SEGMENT_NAME AS TABLE_NAME,  2          SUM(BYTES) / (1024 * 1024 * 1024) "TABLE_SIZE[GB]"  3     FROM DBA_SEGMENTS T  4    WHERE T.SEGMENT_NAME = 'BUSTB_TESTRESULT'  5      AND SEGMENT_TYPE = 'TABLE SUBPARTITION'  6      AND PARTITION_NAME LIKE 'RESULT_PART_201301%'  7    GROUP BY SEGMENT_NAME;rows will be truncatedTABLE_NAME--------------------------------------------------------------------------------BUSTB_TESTRESULTSQL> set line 4000;SQL>  SELECT SEGMENT_NAME AS TABLE_NAME,  2          SUM(BYTES) / (1024 * 1024 * 1024) "TABLE_SIZE[GB]"  3     FROM DBA_SEGMENTS T  4    WHERE T.SEGMENT_NAME = 'BUSTB_TESTRESULT'  5      AND SEGMENT_TYPE = 'TABLE SUBPARTITION'  6      AND PARTITION_NAME LIKE 'RESULT_PART_201301%'  7    GROUP BY SEGMENT_NAME;TABLE_NAME                                                                        TABLE_SIZE[GB]--------------------------------------------------------------------------------- --------------BUSTB_TESTRESULT                                                                      8.19140625SQL> set line 1000;SQL>  SELECT SEGMENT_NAME AS TABLE_NAME,  2          SUM(BYTES) / (1024 * 1024 * 1024) "TABLE_SIZE[GB]"  3     FROM DBA_SEGMENTS T  4    WHERE T.SEGMENT_NAME = 'BUSTB_TESTRESULT'  5      AND SEGMENT_TYPE = 'TABLE SUBPARTITION'  6      AND PARTITION_NAME LIKE 'RESULT_PART_201301%'  7    GROUP BY SEGMENT_NAME;TABLE_NAME                                                                        TABLE_SIZE[GB]--------------------------------------------------------------------------------- --------------BUSTB_TESTRESULT                                                                      8.19140625SQL> col TABLE_NMAE format a40;SQL>  SELECT SEGMENT_NAME AS TABLE_NAME,  2          SUM(BYTES) / (1024 * 1024 * 1024) "TABLE_SIZE[GB]"  3     FROM DBA_SEGMENTS T  4    WHERE T.SEGMENT_NAME = 'BUSTB_TESTRESULT'  5      AND SEGMENT_TYPE = 'TABLE SUBPARTITION'  6      AND PARTITION_NAME LIKE 'RESULT_PART_201301%'  7    GROUP BY SEGMENT_NAME  8  ;  TABLE_NAME                                                                        TABLE_SIZE[GB]--------------------------------------------------------------------------------- --------------BUSTB_TESTRESULT                                                                      8.19140625SQL> col TABLE_NAME format a10;SQL>  SELECT SEGMENT_NAME AS TABLE_NAME,  2          SUM(BYTES) / (1024 * 1024 * 1024) "TABLE_SIZE[GB]"  3     FROM DBA_SEGMENTS T  4    WHERE T.SEGMENT_NAME = 'BUSTB_TESTRESULT'  5      AND SEGMENT_TYPE = 'TABLE SUBPARTITION'  6      AND PARTITION_NAME LIKE 'RESULT_PART_201301%'  7    GROUP BY SEGMENT_NAME;TABLE_NAME TABLE_SIZE[GB]---------- --------------BUSTB_TEST     8.19140625SQL> set heading off;SQL> set heading offSQL> set line 4000SQL>  SELECT SEGMENT_NAME AS TABLE_NAME,                                                       2          SUM(BYTES) / (1024 * 1024 * 1024) "TABLE_SIZE[GB]"  3     FROM DBA_SEGMENTS T  4    WHERE T.SEGMENT_NAME = 'BUSTB_TESTRESULT'  5      AND SEGMENT_TYPE = 'TABLE SUBPARTITION'  6      AND PARTITION_NAME LIKE 'RESULT_PART_201301%'  7    GROUP BY SEGMENT_NAME     8  /BUSTB_TEST     8.19140625SQL> col TABLE_NAME format a20;SQL>  SELECT SEGMENT_NAME AS TABLE_NAME,  2          SUM(BYTES) / (1024 * 1024 * 1024) "TABLE_SIZE[GB]"  3     FROM DBA_SEGMENTS T  4    WHERE T.SEGMENT_NAME = 'BUSTB_TESTRESULT'  5      AND SEGMENT_TYPE = 'TABLE SUBPARTITION'  6      AND PARTITION_NAME LIKE 'RESULT_PART_201301%'  7    GROUP BY SEGMENT_NAME;BUSTB_TESTRESULT         8.19140625SQL> set heading on;SQL>  SELECT SEGMENT_NAME AS TABLE_NAME,  2          SUM(BYTES) / (1024 * 1024 * 1024) "TABLE_SIZE[GB]"  3     FROM DBA_SEGMENTS T  4    WHERE T.SEGMENT_NAME = 'BUSTB_TESTRESULT'  5      AND SEGMENT_TYPE = 'TABLE SUBPARTITION'  6      AND PARTITION_NAME LIKE 'RESULT_PART_201301%'  7    GROUP BY SEGMENT_NAME;TABLE_NAME           TABLE_SIZE[GB]-------------------- --------------BUSTB_TESTRESULT         8.19140625SQL>