[Leetcode] 195. Tenth Line

Problem
How would you print just the 10th line of a file?

For example, assume that file.txt has the following content:

Line 1
Line 2
Line 3
Line 4
Line 5
Line 6
Line 7
Line 8
Line 9
Line 10

Your script should output the tenth line, which is:

Line 10

Wrong Answer

#Remember cases that there are less than 10 lines.head -10 file.txt | tail -1

Correct Answer

sed -n '10p' file.txt

Other Answer

cnt=0while read line && [ $cnt -le 10 ]; do    let 'cnt = cnt + 1'    if [ $cnt -eq 10 ]; then    echo $line    exit 0    fidone < file.txt

awk 'FNR == 10 {print }' file.txt# ORawk 'NR == 10' file.txt

tail -n+10 file.txt|head -1

Reference
http://www.cnblogs.com/fjping0606/p/4997643.html

sed文本流行处理
https://fsp1yjl.github.io/2017/04/25/sed%E6%96%87%E6%9C%AC%E6%B5%81%E8%A1%8C%E5%A4%84%E7%90%86/