二维坐标，x从小到大排列，y从大到小排列

来源：互联网发布：everything微课软件编辑：程序博客网时间：2024/05/19 13:23

目前能想到的最完美的方案，还没得到扩展，仅仅可用于二维数组

重点思路：将xy捆绑到一块排序，因为y是倒叙需要计算下对应正序时的值，也就是拿y组最大值减去当前值，得到x升序y升序组合数组xy，需要考虑到y组位数问题

import java.util.Arrays;public class Test {public static void main(String[] args) {Test test = new Test();int[][] param = new int[][] { { 3, 20 }, { 1, 9 }, { 5, 8 }, { 2, 1 }, { 3, 6 }, { 2, 1 } };int[][] result = test.sortArrayTwoDimension(param);for (int i = 0; i < result.length; i++) {System.out.println(result[i][0] + "  " + result[i][1]);}}public int[][] sortArrayTwoDimension(int[][] param) {int[] x = new int[param.length];int[] y = new int[param.length];for (int i = 0; i < param.length; i++) {int[] temp = param[i];x[i] = temp[0];y[i] = temp[1];}int maxy = 0;for (int i = 0; i < y.length; i++) {if (y[i] > maxy) {maxy = y[i];}}// 将y数组用最大值-原有值获取倒叙值数组int[] sortp = new int[param.length];for (int i = 0; i < y.length; i++) {sortp[i] = maxy - y[i];}// y数组最大长度int ylmax = String.valueOf(maxy).length();long[] xy = new long[param.length];for (int i = 0;i<x.length;i++) {xy[i] = Long.valueOf(String.valueOf(x[i]) + Test.addZeroForNum(String.valueOf(sortp[i]), ylmax));}Arrays.sort(xy);int index = 0;int[][] result = new int[x.length][2];for (int j = 0; j < xy.length; j++) {for (int i = 0; i < x.length; i++) {if (xy[j] == Long.valueOf(String.valueOf(x[i]) + Test.addZeroForNum(String.valueOf(sortp[i]), ylmax))) {result[index] = new int[]{x[i],y[i]};index++;break;}}}return result;}public static String addZeroForNum(String str, int strLength) {int strLen = str.length();if (strLen < strLength) {while (strLen < strLength) {StringBuffer sb = new StringBuffer();sb.append("0").append(str);str = sb.toString();strLen = str.length();}}return str;}}

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