codeforces——D. Shovel Sale
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1LL——long long类型的1,其实就是1。
#include <iostream>using namespace std;int main() { //cout<<1LL;//long long 型的1 long long n; cin>>n; long long num=0,ans=0; while (num*10+9<=n+n-1) num=num*10+9; for(long long i=num;i<=n+n-1;i+=num+1) { ans+=(i-max(1ll,i-n)*2+1)/2;//解题的关键,求各个区间的数量 } cout<<ans<<endl; return 0;}
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