leetcode 679. 24 Game 24点游戏
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You have 4 cards each containing a number from 1 to 9. You need to judge whether they could operated through *, /, +, -, (, ) to get the value of 24.
Example 1:
Input: [4, 1, 8, 7]
Output: True
Explanation: (8-4) * (7-1) = 24
Example 2:
Input: [1, 2, 1, 2]
Output: False
Note:
The division operator / represents real division, not integer division. For example, 4 / (1 - 2/3) = 12.
Every operation done is between two numbers. In particular, we cannot use - as a unary operator. For example, with [1, 1, 1, 1] as input, the expression -1 - 1 - 1 - 1 is not allowed.
You cannot concatenate numbers together. For example, if the input is [1, 2, 1, 2], we cannot write this as 12 + 12.
本题题意很简单,最笨的方法就是直接考虑所有的情况
代码如下:
#include <iostream>#include <vector>#include <map>#include <set>#include <queue>#include <stack>#include <string>#include <climits>#include <algorithm>#include <sstream>#include <functional>#include <bitset>#include <numeric>#include <cmath>#include <regex>using namespace std;class Solution{public: bool judgePoint24(vector<int>& nums) { sort(nums.begin(), nums.end()); do { if (valid(nums)) return true; } while (next_permutation(nums.begin(), nums.end())); return false; } bool valid(vector<int>& nums) { double a = nums[0], b = nums[1], c = nums[2], d = nums[3]; if (valid(a + b, c, d) || valid(a - b, c, d) || valid(a*b, c, d) || b != 0 && valid(a / b, c, d)) return true; if (valid(a, b + c, d) || valid(a, b - c, d) || valid(a, b*c, d) || c != 0 && valid(a, b / c, d)) return true; if (valid(a, b, c + d) || valid(a, b, c - d) || valid(a, b, c*d) || d != 0 && valid(a, b, c / d)) return true; return false; } bool valid(double a, double b, double c) { if (valid(a + b, c) || valid(a - b, c) || valid(a*b, c) || b != 0 && valid(a / b, c)) return true; if (valid(a, b + c) || valid(a, b - c) || valid(a, b*c) || c != 0 && valid(a, b / c)) return true; return false; } bool valid(double a, double b) { if (abs(a + b - 24.0) < 0.0001 || abs(a - b - 24.0) < 0.0001 || abs(a*b - 24.0) < 0.0001 || b!= 0 && abs(a / b - 24.0) < 0.0001) return true; return false; }};
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