(补充)python oss获取指定目录下所有文件,并排序返回
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# -*- coding: utf-8 -*-import sysimport oss2import timeimport tracebackPREFIX = 'http://'class find_oss_file(): def __init__(self): pass # ossinfo { # ossinfo ={ACCESS_KEY_ID,ACCESS_KEY_SECRET,ENDPOINT,BUCKETNAME_XLS} # timerange 时间毫秒值 # urlload 文件目录 def findfile(self, ossinfo, urlload): result = {} urlDict = {} urlList = [] try: auth = oss2.Auth(ossinfo['ACCESS_KEY_ID'], ossinfo['ACCESS_KEY_SECRET']) bucket = oss2.Bucket(auth, ossinfo['ENDPOINT_OUT'], ossinfo['BUCKETNAME_XLS']) for filename in oss2.ObjectIterator(bucket, prefix='%s/'%urlload): sourceURL = PREFIX + ossinfo['BUCKETNAME_XLS'] + '.' + ossinfo['ENDPOINT_OUT'] +'/'+ filename.key sourceTime = filename.last_modified if sourceTime in urlDict.keys(): #最多保证10个相同时间的路径不覆盖 sourceTime += 0.1 urlDict[sourceTime] = sourceURL newurl = sorted(urlDict.items(), key=lambda asd: asd[0], reverse=True) for u in newurl: urlList.append(u[1]) result['fileurl'] = urlList result['errorcode'] = 0 return result except Exception, ex: result['errorcode'] = -1 result['errortext'] = '%s_%s:%s' % (traceback.print_exc(), Exception, ex) return result
上一篇:python oss上获取指定bucket,指定时间范围内文件 http://blog.csdn.net/persistencequxi/article/details/78882288
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