lua5.1.5 c++交互

#include "stdafx.h"#pragma comment(lib,"lua5.1.5.lib")extern "C"{#include <lua.h>#include <lualib.h>#include <lauxlib.h>#include <stdlib.h>}extern "C" int add(lua_State *Ls){//获取参数数量int num = lua_gettop(Ls);//获取栈顶索引值可以参数数量printf("参数数量:%d\r\n",num);int Ref = 0;for (int i = 1; i <= num; i++) {Ref += lua_tointeger(Ls, i);}//把返回值压入堆栈lua_pushinteger(Ls,Ref);lua_pushinteger(Ls, 1111);lua_pushinteger(Ls, 2222);return 3;//返回参数的个数}int main(){//创建lua环境lua_State *L= luaL_newstate();//打开lua所有库支持luaL_openlibs(L);//注册Lua函数lua_register(L,"累加测试", add);//调用lua函数//先把函数压入堆栈lua_getglobal(L,"累加测试");//再把参数压栈lua_pushinteger(L, 1);lua_pushinteger(L, 2);lua_pushinteger(L, 3);lua_pushinteger(L, 4);lua_pushinteger(L, 5);//调用函数lua_call(L, 5, 3);//参数2是传入的参数个数，参数3是返回值个数//获取返回值int aa1 = lua_tointeger(L, 1);int aa2 = lua_tointeger(L, 2);int aa3 = lua_tointeger(L, 3);printf("返回值:%d  %d  %d\r\n",aa1, aa2, aa3);//关闭lualua_close(L);system("pause");    return 0;}

我用的是修改版本的lua5.1.5所以才支持中文命名函数