vue vue搜索 vue模糊搜索

1、使用vue来实现一般搜索

<form action="" @submit="submitQuery" class="all_two">     <el-input v-model="input" placeholder="请输入内容" ref="search" style="width:300px;"></el-input></form><div class="all_three">      <div v-for="item in this.$store.state.chufang.alldata">            <div v-for="item1 in queryDate(item.cabinet)" >                 <input type="checkbox" name="checkbox"  value="checkbox" style="zoom:200%;" :checked="item1.checks==0? true:false">                 <span>{{item1.name}}</span>            </div>       </div></div>

submitQuery:function(){    this.query = this.$refs.search.value.trim();}, 

queryDate:function(list){     if (this.query === '') {         return list     }      return list.filter((item)=>{         if(item.name.indexOf(this.query) != -1){            return item;          }     })},

2、vue模糊搜索，原理都是一样的

 <el-form :inline="true" :model="formInline" class="demo-form-inline mt15">      <el-form-item>          <el-input v-model="formInline.name" ref="search"   placeholder="姓名"></el-input>      </el-form-item>      <el-form-item>           <el-input v-model="formInline.phone" ref="search1"  placeholder="手机号"></el-input>      </el-form-item>      <el-form-item>            <el-button type="primary" @click="onSubmit">筛选</el-button>      </el-form-item> </el-form>

onSubmit() {      this.query = this.$refs.search.value.trim();      this.query1 = this.$refs.search1.value.trim();},queryDate:function(list){      if (this.query === '' && this.query1 === '') {         return list      }       else if (this.query !== '' && this.query1 === '') {         return list.filter(item => {              if (item.name.indexOf(this.query) !== -1) {                  return item               }          })       }        else if (this.query === '' && this.query1 !== '') {          return list.filter(item => {               if (item.mobile.indexOf(this.query1) !== -1) {                   return item                 }           })        }         else if (this.query !== '' && this.query1 !== '') {           return list.filter(item => {                if (item.name.indexOf(this.query) !== -1 && item.mobile.indexOf(this.query1) !== -1) {                   return item                }           })        }},