利用XMLHTTP 从其他页面获取数据

来源:互联网 发布:2017网络新兴词汇 编辑:程序博客网 时间:2024/05/03 11:56

我们在编写ASP代码的时候,大家都知道可以通过post或者get获得form表单的数据,那么我们如何直接获得其他页面上的数据呢?这就要借助xmlhttp协议了。xmlhttp是xmldom技术的一部分。

下面的代码就是一个很简单的例子,我们利用xmlhttp技术,把http://www.codetoad.com/站点首页的代码以xml的形式完全获取,并且在页面中输出。

<%
? Dim objXMLHTTP, xml
? Set xml = Server.CreateObject("Microsoft.XMLHTTP")
?
? xml.Open "GET", "http://www.codetoad.com/", False
? ' Pull the data from the web page
? xml.Send

? Response.write "Here's the html we now have in our xml object"
? Response.write "


"
? Response.Write "

"<br />? Response.Write xml.responseText<br />? Response.Write ""
? Response.write "


"
?Response.write " Now here's how the page looks:

"
? Response.Write xml.responseText
?
? Set xml = Nothing
%>

下面是另一个实例

<%
dim objHTTP , objXML , objXSL
set objHTTP = Server.CreateObject("Microsoft.XMLHTTP")
objHTTP.open "GET", "http://p.moreover.com/cgi-local/page?c=Pop%20music%20reviews&o=xml", false
objHTTP.send
set objXML = objHTTP.responseXML
set objXSL=Server.CreateObject("microsoft.xmldom")
objXSL.async=false

objXSL.load(Server.MapPath("style.xsl"))

if (objXSL.parseError.errorCode = 0) then
??? Response.Write(objXML.transformnode(objXSL))
else
??? Response.Write "Error: " & objXSL.parseError.reason & " URL:" & objXSL.url
end if

Set objHTTP = Nothing
Set objXML = Nothing
Set objXSL = Nothing
%>

style.xsl:
http://www.w3.org/TR/WD-xsl">
   






 


     
      
        
          
            
                  
            
              
            

            
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