Cross ＋ Roads = Danger

// C R O S S// ＋R O A D S// -----------// D A N G E R//分析：D必为0或1，R必为偶数#include <iostream>using namespace std;int main(void){int c,r,o,s;int a,d,n,g,e;int temp,t,nn;for ( d=0; d<=1; d++ ){for ( r=0; r<=8; r+=2 ){if ( r==d ) continue;for ( o=0; o<=9; o++ ){if ( o==d || o==r ) continue;for ( a=0; a<=9; a++ ){if ( a==d || a==r || a==o ) continue;for ( s=0; s<=9; s++ ){if ( s==d || s==r || s==o || s==a ) continue;for ( c=0; c<=9; c++ ){if ( c==d || c==r || c==o || c==a || c==s ) continue;temp = (c*10000+r*1000+o*100+s*10+s) + (r*10000+o*1000+a*100+d*10+s);if ( temp%10 != r ) continue;if ( temp/100000 != d ) continue;if ( (temp/10000)%10 != a ) continue;t = temp;for ( nn=1; nn<=4; nn++ ){if ( nn==2 ) e = t%10;else if ( nn==3 ) g = t%10;else if ( nn==4 ) n = t%10;t /= 10;}if ( e==g || e==n || g==n ) continue;if ( e==c || e==r || e==o || e==s || e==a || e==d ) continue;if ( g==c || g==r || g==o || g==s || g==a || g==d ) continue;if ( n==c || n==r || n==o || n==s || n==a || n==d ) continue;cout<<c<<r<<o<<s<<s<<" + "<<r<<o<<a<<d<<s<<" = "<<d<<a<<n<<g<<e<<r;}}}}}}cin.get();return 0;}