获取多个网卡地址

来源：互联网发布：步兵番号知乎编辑：程序博客网时间：2024/05/21 09:10

#include < windows.h >
#include < wincon.h >
#include < stdlib.h >
#include < stdio.h >
#include < time.h >
// 因为是通过NetAPI来获取网卡信息，所以需要包含其题头文件nb30.h
#include <Nb30.h>

# pragma comment(lib, "Netapi32.lib")

typedef struct _ASTAT_
{
ADAPTER_STATUS adapt;
NAME_BUFFER NameBuff [30];
}ASTAT, * PASTAT;

// 定义一个存放返回网卡信息的变量
ASTAT Adapter;

// 输入参数：lana_num为网卡编号，一般地，从0开始，但在Windows 2000中并不一定是连续分配的
void getmac_one (int lana_num)
{
NCB ncb;
UCHAR uRetCode;
memset( &ncb, 0, sizeof(ncb) );
ncb.ncb_command = NCBRESET;
// 指定网卡号
ncb.ncb_lana_num = lana_num;

// 首先对选定的网卡发送一个NCBRESET命令，以便进行初始化
uRetCode = Netbios( &ncb );
printf( "The NCBRESET return code is: 0x%x /n", uRetCode );

memset( &ncb, 0, sizeof(ncb) );
ncb.ncb_command = NCBASTAT;
ncb.ncb_lana_num = lana_num; // 指定网卡号
strcpy( (char *)ncb.ncb_callname, "* " );

// 指定返回的信息存放的变量
ncb.ncb_buffer = (unsigned char *) &Adapter;
ncb.ncb_length = sizeof(Adapter);

// 接着，可以发送NCBASTAT命令以获取网卡的信息
uRetCode = Netbios( &ncb );
printf( "The NCBASTAT return code is: 0x%x /n", uRetCode );

if ( uRetCode == 0 )
{
  // 把网卡MAC地址格式化成常用的16进制形式，如0010-A4E4-5802
  printf( "The Ethernet Number[%d] [Page] is: %02X%02X-%02X%02X-%02X%02X/n",
   lana_num,
   Adapter.adapt.adapter_address[0],
   Adapter.adapt.adapter_address[1],
   Adapter.adapt.adapter_address[2],
   Adapter.adapt.adapter_address[3],
   Adapter.adapt.adapter_address[4],
   Adapter.adapt.adapter_address[5] );
}
}

int main(int argc, char* argv[])
{
NCB ncb;
UCHAR uRetCode;
LANA_ENUM lana_enum;
memset( &ncb, 0, sizeof(ncb) );
ncb.ncb_command = NCBENUM;
ncb.ncb_buffer = (unsigned char *) &lana_enum;
ncb.ncb_length = sizeof(lana_enum);

// 向网卡发送NCBENUM命令，以获取当前机器的网卡信息，如有多少个网卡、每张网卡的编号等
uRetCode = Netbios( &ncb );
printf( "The NCBENUM return code is: 0x%x /n", uRetCode );

if ( uRetCode == 0 )
{
printf( "Ethernet Count is : %d/n", lana_enum.length);

// 对每一张网卡，以其网卡编号为输入编号，获取其MAC地址

  for ( int i=0; i< lana_enum.length; ++i)
  {
   getmac_one( lana_enum.lana[i]);
  }
}

system("pause");

return 0;
}