关于公民身份证号码15位与18位互相转化的问题

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--SQL SERVER 15位身份证号转18位身份证 

CREATE FUNCTION ID15TO18 (@id15 char(15))
RETURNS CHAR(
18) AS
BEGIN
    DECLARE @ID18 CHAR(
18),@S18 bigint
   
    SET @S18 = ( (SUBSTRING(@ID15,
1,1)*7) + (SUBSTRING(@ID15,2,1)*9) + (SUBSTRING(@ID15,3,1)*10)
       + (SUBSTRING(@ID15,
4,1)*5) + (SUBSTRING(@ID15,5,1)*8) + (SUBSTRING(@ID15,6,1)*4) + (1*2) + (9*1)
       + (SUBSTRING(@ID15,
7,1)*6) + (SUBSTRING(@ID15,8,1)*3) + (SUBSTRING(@ID15,9,1)*7)
       + (SUBSTRING(@ID15,
10,1)*9)+ (SUBSTRING(@ID15,11,1)*10)+ (SUBSTRING(@ID15,12,1)*5)
       + (SUBSTRING(@ID15,
13,1)*8) +(SUBSTRING(@ID15,14,1)*4) + (SUBSTRING(@ID15,15,1)*2) ) % 11
   
    SET @ID18 = SUBSTRING(@ID15,
1,6) + '19' + SUBSTRING(@ID15,7,9) +
        CASE
            WHEN @S18 =
0 THEN '1'
            WHEN @S18 =
1 THEN '0'
            WHEN @S18 =
2 THEN 'X'
            WHEN @S18 =
3 THEN '9'
            WHEN @S18 =
4 THEN '8'
            WHEN @S18 =
5 THEN '7'
            WHEN @S18 =
6 THEN '6'
            WHEN @S18 =
7 THEN '5'
            WHEN @S18 =
8 THEN '4'
            WHEN @S18 =
9 THEN '3'
            WHEN @S18 =
10 THEN '2'
        END
   
    RETURN @ID18
END


GO


SELECT DBO.ID15TO18(
'????????????????')

DROP FUNCTION ID15TO18

 

 

 

-- 18位身份证号转15位身份证

CREATE FUNCTION ID18TO15 (@id18
char(18))
RETURNS CHAR(
15) AS
BEGIN
    DECLARE @ID15 CHAR(
15)
   
    SET @ID15
= SUBSTRING(@id18,1,6) + SUBSTRING(@id18,9,9)
   
    RETURN @ID15
END


GO


SELECT DBO.ID18TO15(
'3210*****605026619')

DROP FUNCTION ID18TO15

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