tomcat发布基于jersey的WebService（二）

周末继续学习jersey，测试了几个get和post方式的webservice请求，并模拟客户端测试调用情况。在google中找到了这么一篇相关的文章：

REST: CRUD with JAX-RS (Jersey) 。  结果做到一半出了问题，服务端总是获取不到客户端请求的数据流内容！调试了一个下午未果，却在第二天如梦方醒般的找到了原因。教训1：学习下http协议；教训2：老外的东西不一定是对的。

 

周末的测试主要还是基于jersey的webservice服务。对get和post两种方式发送请求的几种情况都做了简单的示例（上传文件的情况未测试，待续）。

 

service端：

@Path("/hello")public class HelloService {@GET@Produces("text/plain")public String helloWorld(){return "hello world";}/* * post param test */@POST @Path("echo")@Consumes("application/x-www-form-urlencoded") public String echo(@FormParam("msg") String msg){return "are you say "+msg;}/* * get param test */@GET@Path("sex")@Produces("text/plain")public String getSex(@PathParam("name") String name){return "male";}/* * get {} request * http://houfeng:8080/jerseyWebServiceTest/services/hello/age/houfeng */@GET@Path("age/{name}")@Produces("text/plain")public String getAge(@PathParam("name") String name){return "18";}/* * get {} request * http://houfeng:8080/jerseyWebServiceTest/services/hello/223232323 */@GET@Path ("{id}")@Produces ("application/xml")public StreamingOutput retrieveCustomer(@PathParam ("id") String customerId) { String customerDetails = "hou,feng,232"; final String[] details = customerDetails.split(","); return new StreamingOutput() { public void write(OutputStream outputStream) { PrintWriter out = new PrintWriter(outputStream); out.println("<?xml version=/"1.0/" encoding=/"UTF-8/"?>"); out.println("<customer>"); out.println("<firstname>" + details[0] + "</firstname>"); out.println("<lastname>" + details[1] + "</lastname>"); out.println("<zipcode>" + details[2] + "</zipcode>"); out.println("</customer>"); out.close(); } }; }// get vs post @GET@Path("test_get")@Produces("text/plain")public String getTest1(@PathParam("name") String name, @Context HttpServletRequest request){System.out.println("name:"+name);// nullString result;result = request.getParameter("name");System.out.println("name="+result); //houfengresult+= "--------"+request.getContextPath(); return result;}/* * get 方式 正确的获取参数方法 @QueryParam 或者 用 request； url里有参数的用PathParam */@GET@Path("test_get2")@Produces("text/plain")public String getTest11(@QueryParam("name") String name, @Context HttpServletRequest request){System.out.println("name:"+name);// houfengString result;result = request.getParameter("name");System.out.println("name="+result); //houfeng result+= "--------"+request.getContextPath(); return result;} @POST@Path("test_post1")@Consumes("application/x-www-form-urlencoded") @Produces("text/plain")public String getTest2(@FormParam("name") String name){ System.out.println(name);//houfengString result=name; return result;}@POST@Path("test_post2")@Consumes("application/x-www-form-urlencoded") @Produces("text/plain")public String getTest22(@QueryParam("name") String name){System.out.println("name:"+name);//houfeng,但是有警告。提示用FormParamString result = name; return result;}@POST@Path("test_post3") @Produces("text/plain")public String getTest2222(String entity, @Context HttpServletRequest request){System.out.println("entity:"+entity);//hello 传入方式：resource.entity("hello").post(String.class);String result; result= "--------"+request.getContextPath(); return result;}@POST@Path("test_post4")//@Consumes("application/xml"),这样就会出错；@Consumes("application/x-www-form-urlencoded") 可以。@Produces("text/plain")public String getTest22222(InputStream is, @Context HttpServletRequest request) throws Exception{byte[] buf = new byte[is.available()];is.read(buf);System.out.println("buf:"+new String(buf));String result; result= "--------"+request.getContextPath(); return result;}

 

客户端可以采用两种方式测试。

1，采用jersey实现的测试api：jersey-twitter-client-1.0-SNAPSHOT-jar-with-dependencies.jar

2，采用apache httpclient 模拟客户端的各种请求。

上面提到的参考e文中是采用的第二种方式。在这里我使用jersey测试api来实现。

public void testHelloService() throws URISyntaxException {Client client = Client.create();URI u = new URI("http://houfeng:8080/jerseyWebServiceTest/services/hello");System.out.println(u);WebResource resource = client.resource(u);//getString result = resource.get(String.class);System.out.println(result);//get paramu = new URI("http://houfeng:8080/jerseyWebServiceTest/services/hello/sex");System.out.println(u);resource = client.resource(u);MultivaluedMapImpl params = new MultivaluedMapImpl();params.add("name", "houfeng");result = resource.queryParams(params).get(String.class);System.out.println(result);u =new URI("http://houfeng:8080/jerseyWebServiceTest/services/hello/test_get");System.out.println(u);resource = client.resource(u);params = new MultivaluedMapImpl();params.add("name", "houfeng");result = resource.queryParams(params).get(String.class);System.out.println(result);u =new URI("http://houfeng:8080/jerseyWebServiceTest/services/hello/test_get2");System.out.println(u);resource = client.resource(u);params = new MultivaluedMapImpl();params.add("name", "houfeng");result = resource.queryParams(params).get(String.class);System.out.println(result); u =new URI("http://houfeng:8080/jerseyWebServiceTest/services/hello/test_post1");System.out.println(u);resource = client.resource(u);params = new MultivaluedMapImpl();params.add("name", "houfeng");result = resource.type(MediaType.APPLICATION_FORM_URLENCODED).post(String.class,params);System.out.println(result);u =new URI("http://houfeng:8080/jerseyWebServiceTest/services/hello/test_post2");System.out.println(u);resource = client.resource(u);params = new MultivaluedMapImpl();params.add("name", "houfeng");result = resource.queryParams(params).type(MediaType.APPLICATION_FORM_URLENCODED).post(String.class);System.out.println(result);u =new URI("http://houfeng:8080/jerseyWebServiceTest/services/hello/test_post3");System.out.println(u);resource = client.resource(u); result = resource.entity("hello").post(String.class);System.out.println(result);u =new URI("http://houfeng:8080/jerseyWebServiceTest/services/hello/test_post4");System.out.println(u);resource = client.resource(u); String buf = "inputstream content.";ByteArrayInputStream bais = new ByteArrayInputStream(buf.getBytes());result = resource.entity(bais).post(String.class);System.out.println(result);}

 

过程中遇到的问题就是提交流的时候，错误的参考了e文中 “@Consumes ("application/xml") ”的请求类型！ 结果导致service 端 接受请求的方法参数InputStream 得不到内容。换作@Context HttpServeltRequest request 参数也无济于事。于是在网上搜索，在一个国外论坛中有人提到相似的问题“上传文件得不到流里的内容，但是jetty里可以，tomcat里不可以。？”。好像没有太大参考，但我也试了下，还是失败。。。

今天修改提交类型注解为：@Consumes("application/x-www-form-urlencoded") ，测试通过！终于才恍然大悟：application/xml是客户端接受的内容类型。哎，是应该学习下http协议的相关知识，这样的问题耽误了大半天的时间！

    另外，对于jax-ws中几个注解，简单总结下：
       QueryParam--url ? 后面表示的参数  .  get post 通用.
       PathParam---url中的一部分，例如用{}表示的url中的一部分。get post 通用。
       FormParam---post提交的form表单参数。     用于 post     

  （ 其他几个param稍后再学习）。