Json+AjaxPro

来源:互联网 发布:json rpc 1.0 编辑:程序博客网 时间:2024/05/22 13:39

需要添加Newtonsoft.Json.dll引用

 

服务器端:

/// <summary>
/// 把DataSet转化Json对象
/// </summary>[;
/// <param name="ds">数据集</param>
/// <param name="JsonName">Json数据的根元素名称</param>

/// <param name="ParName">需要转化数据集中名称的数组</param>

/// <returns></returns>
private static string DataSetToJson(DataSet ds, string JsonName, string[] ParName)
{
     try
     {
           string josn = "{ /"" + JsonName + "/":[";
           string temp = "";
           for (int j = 0; j < ds.Tables[0].Rows.Count; j++)
           {
                    temp = temp + "{";
                    for (int i = 0; i < ParName.Length; i++)
                    {
                        temp += "/'" + ParName[i] + "/':/"" + ds.Tables[0].Rows[j][ParName[i]] + "/"";
                        if (i != ParName.Length - 1)
                        {
                            temp = temp + ",";
                        }
                    }
                    temp = temp + "}";
                }
                josn = josn + temp + "]}";
                return josn;
        }
        catch (Exception ex)
        {
                throw ex;
        }
}

 

/// <summary>
/// 接收object类型对象,将其转换为json字符串
/// </summary>
/// <param name="value">接收Object对象</param>
/// <returns>json字符串</returns>
private static string MySerializeObject(Object value)
{
      System.IO.StringWriter sw = new System.IO.StringWriter(CultureInfo.InvariantCulture);
      JsonSerializer jsonSerializer = new JsonSerializer();
      jsonSerializer.ReferenceLoopHandling = ReferenceLoopHandling.Ignore;
      using (JsonTextWriter jsonWriter = new JsonTextWriter(sw))
      {
            jsonWriter.Formatting = Newtonsoft.Json.Formatting.Indented;
            jsonSerializer.Serialize(jsonWriter, value);
       }
       return sw.ToString();
}

 

Magreement是一个实体类。

 

/// <summary>
/// 将json字符串转化为对象
/// </summary>
/// <param name="str"></param>
/// <returns></returns>
private static Magreement MyDeserializeObject(string str)
{
        Magreement agreement = (Magreement)JsonConvert.DeserializeObject(str, typeof(Magreement));
        return agreement;
}

 

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