hibernate组建映射

当一个用户表中字段比较多，而有些字段是不常用，则可以用组件映射

 

基本信息：

private Long id;private String username;private String password;private UserMessage message ;

 

组件信息 ，UserMessage

private String address;private String email;private String phone;private String postcode;private Userinfo info ;

 

private Userinfo info 这里是为了配置双向关联

 

<hibernate-mapping> <class name="com.pojo.Userinfo" table="USERINFO" schema="ZM"> <id name="id" type="java.lang.Long"> <column name="ID" precision="10" scale="0" /> <generator class="increment" /> </id> <property name="username" type="java.lang.String"> <column name="USERNAME" length="100" /> </property> <property name="password" type="java.lang.String"> <column name="PASSWORD" length="100" /> </property> <component name="message" class="com.pojo.UserMessage"> <parent name="info" /> <property name="address" type="java.lang.String"> <column name="ADDRESS" length="100" /> </property> <property name="email" type="java.lang.String"> <column name="EMAIL" length="100" /> </property> <property name="phone" type="java.lang.String"> <column name="PHONE" length="100" /> </property> <property name="postcode" type="java.lang.String"> <column name="POSTCODE" length="100" /> </property> </component> </class></hibernate-mapping>

 

组件映射用到了  <component name="message" class="com.pojo.UserMessage">

配置双向关联 ： <parent name="info" />

 

测试类：

public static void main(String[] args) {Userinfo info = new Userinfo() ;info.setId(new Long(1)) ;info.setUsername("zhangsan") ;info.setPassword("111111") ;UserMessage message = new UserMessage() ;message.setAddress("西里小区") ;message.setEmail("[e-mail]") ;message.setPhone("123456") ;message.setPostcode("100082") ;info.setMessage(message) ;message.setInfo(info) ;HibernateTestcompent.add(info) ;HibernateTestcompent.load(message) ;}public static void add(Userinfo userinfo) {session = HibernateManager.openSession();try {session.save(userinfo);HibernateManager.closeSession();} catch (Exception e) {HibernateManager.rollbackTransaction();}}@SuppressWarnings("unchecked")public static void load() {session = HibernateManager.openSession();try {Userinfo user = (Userinfo) session.get(Userinfo.class, new Long(1));System.out.println(user.getId());System.out.println(user.getUsername());System.out.println(user.getPassword());System.out.println(user.getMessage().getAddress());System.out.println(user.getMessage().getEmail());System.out.println(user.getMessage().getPhone());System.out.println(user.getMessage().getPostcode());HibernateManager.closeSession();} catch (Exception e) {e.printStackTrace();HibernateManager.rollbackTransaction();}}public static void load(UserMessage message) {Userinfo info = message.getInfo();System.out.println(info.getId());System.out.println(info.getUsername());System.out.println(info.getPassword());System.out.println(message.getAddress());System.out.println(message.getEmail());System.out.println(message.getPhone());System.out.println(message.getPostcode());}

 

测试结果：

 

Hibernate:
    select
        max(ID)
    from
        USERINFO
Hibernate:
    insert
    into
        ZM.USERINFO
        (USERNAME, PASSWORD, ADDRESS, EMAIL, PHONE, POSTCODE, ID)
    values
        (?, ?, ?, ?, ?, ?, ?)
3
zhangsan
111111
西里小区
[e-mail]
123456
100082