统计一串字符串中，单词的个数，并输出这些单词，测试例子

#include "stdio.h"#define FOR_TEST#define MAX_WORD_LEN 50#define MAX_WORD_NUM 128#define MAX_STRING_LEN 1024char achWord[MAX_WORD_NUM][MAX_WORD_LEN] = {0};#ifdef FOR_TEST char achTmp[MAX_STRING_LEN] = {"my@1ping423get123"};#else char achTmp[MAX_STRING_LEN] = {0};#endifint IsCharUpperT(char c){ return ((c >= 'A' && c <= 'Z') ? 1 : 0);}int IsCharLowerT(char c){ return ((c >= 'a' && c <= 'z') ? 1 : 0);}int main(void){ char *pStr = NULL; int nIdx = 0; int nWordIdx = 0; int nLoop = 0; int nFlag = 0;#ifdef FOR_TEST#else printf("input a string for count word:"); scanf("%s", achTmp);#endif pStr = achTmp; printf("the string is: %s/n/n", achTmp); while (*pStr) { if (IsCharUpperT(*pStr) || IsCharLowerT(*pStr)) { achWord[nIdx][nWordIdx++] = *pStr; nFlag = 1; } else { if (nFlag) { nIdx++; nWordIdx = 0; nFlag = 0; } } pStr++; } printf("count %d words list:/n", nIdx); nWordIdx = 0; for (nLoop = 0; nLoop < nIdx; nLoop++) { printf("/t%s/n", achWord[nLoop]); } return 0;}