poj3672 Long Distance Racing留念下，惨痛的教训

http://acm.pku.edu.cn/JudgeOnline/problem?id=3672

此题意思为：在时间允许范围内，走一个来回，最远能走多远

 

#include<stdio.h>int main(){long m,t,i,sum,temp;int u,f,d;char c;while(scanf("%ld%ld%d%d%d",&m,&t,&u,&f,&d)!=EOF){sum=0;for(i=0;i<t;i++){scanf("/n%c",&c);/*去回车，在用scanf（）输入单个字符时要去空格或回车*/if(sum<=m){temp=i;if(c=='u'||c=='d')sum+=u+d;else if(c=='f')sum+=2*f;}}printf("%ld/n",temp);}return 0;}