C/C++传递二维数组［转载］

#include <stdio.h>void func(int n, char str[][5]){ int i; for (i = 0; i < n; i++) { printf("/nstr[%d] = %s/n", i, str[i]); }}void main(){ char str[][5] = {"abc", "def", "ghi"}; func(3, str);}//方法二，形参声明为指向数组的指针。#include <stdio.h>void func(int n, char (*str)[5]){ int i; for (i = 0; i < n; i++) { printf("/nstr[%d] = %s/n", i, str[i]); }}void main(){ char str[][5] = {"abc", "def", "ghi"}; func(3, str);}//方法三，形参声明为指针的指针。#include <stdio.h>void func(int n, char **str){ int i; for (i = 0; i < n; i++) { printf("/nstr[%d] = %s/n", i, str[i]); }}void main(){ char *p[3]; char str[][5] = {"abc", "def", "ghi"}; p[0] = &str[0][0]; p[1] = str[1]; p[2] = str[2]; func(3, p);} 转载：http://kavine.blogbus.com/logs/31866211.html

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我完善了一些（只是个示意）：

 

for( j = 0 ; j < col ; j++ ){printf("%2d", *(array+i*col+j));}printf("/n");}}int main(int argc, char *argv[]){char *p[3];char str[][5] = {"abc","def","ghi"};p[0] = &str[0][0];p[1] = str[1];p[2] = str[2];func(3, p);int array[3][2] = {{1,2},{3,4},{5,6}};funcInt(&array[0][0], 3, 2);}