用汉语法读 -2^31 ~ 2^31-1 范围内的一个整数 （递归法）

 

 

#include <iostream>
using namespace std;

const char Cname[10][3] = {"", "一", "二", "三", "四", "五", "六", "七", "八", "九"};

void print(long number)
{
 if(number==0)
  cout<<"零";
 if (number < 0)
 {
  cout<<"负 ";
  long fnumber=abs(number);
  print(fnumber);
 }
    if (number < 10)
 {
        cout << Cname[number];
    }
 else if (number < 100)
 {
        print(number / 10);
        cout << "十";
        print(number % 10);
    }
 else if (number < 1000)
 {
        print(number / 100);
        cout << "百";
        print(number % 100);
    }
 else if (number < 10000)
 {
        print(number / 1000);
        cout << "千";
        print(number % 1000);
    }
 else if (number < 100000000)
 {
        print(number / 10000); // 打印万位以前的数字。
        cout << "万";
        print(number % 10000); // 打印万位以后的数字。
    }
 else
 {
        print(number / 100000000);
        cout << "亿";
        print(number % 100000000);
    }
}

int main()
{
    long number;
    while (cin >> number)
        print(number);
    return 0;
}

 

 

 

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练习使用二维字符常量：

 

#include <string>
#include <iostream>
using namespace std;
int main()
{
 int a,b,year;
 char gz[6]; //用来表示干支的字符变量

 //注意：下面两个语句中{}内的引号和逗号不能为全角字符
 static char tg[10][3]={"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};
 static char dz[12][3]={"子","丑","寅","卯","辰","巳","午","未","申","酉","戍","亥"};
 printf("请输入一个年份：");
 scanf("%d",&year);
 a=(year-1804)%10; //以1804年为参考年份，1804年是甲子年
 b=(year-1804)%12;
 strcpy(gz,tg[a]);
 strcat(gz,dz[b]);
 printf("%d年的干支为：%s/n",year,gz);
 return 0;
}