函数参数传递实验

来源:互联网 发布:淘宝内衣小学生模特 编辑:程序博客网 时间:2024/06/15 06:07

#include <stdio.h>

 

 

float f1(float a, float b)

{

printf("a = %f, b = %f/n", a, b);

printf("a+b = %f/n", a+b);

return (a+b);

}

 

float f2(double a)

{

printf("a = %f/n", a);

return (float)a;

}

 

typedef float (*FUNC)();

 

int main()

{

int params[2] = {1066192077, 1066192077};

FUNC func1 = NULL;

float ret = 0;

 

func1 = (FUNC)f1;

ret = func1(params[0], params[1]);

 

printf("ret = %d/n", (int)ret);

 

func1 = (FUNC)f2;

params[0] = -858993459;

params[1] = 1073794252; 

ret = func1(params[0], params[1]);

printf("ret = %f/n", ret);

 

return 0;

}

 

 

 

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