hdu 1406

#include<stdio.h>int perfect(int n){int i,sum;sum=0;for(i=1;i<n/2+1;i++)if(n%i==0)sum+=i;if(sum==n)return 1;elsereturn 0;}int main(){int i,n,count,a,b,t;scanf("%d",&n);while(n--){count=0;scanf("%d%d",&a,&b);if(a>b){t=a;a=b;b=t;}for(i=a;i<=b;i++)if(perfect(i))count++;printf("%d/n",count);}}

贱题！！！

要考虑 num1不是总比num2小，“请输出num1和num2之间存在的完数个数”