HDU 2333 / PKU 3497 (贪心算法+二分)
来源:互联网 发布:python opencv 去水印 编辑:程序博客网 时间:2024/05/18 18:45
Assemble
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 29 Accepted Submission(s): 21
Problem Description
Recently your team noticed that the computer you use to practice for programming contests is not good enough anymore. Therefore, you decide to buy a new computer.
To make the ideal computer for your needs, you decide to buy separate components and assemble the computer yourself. You need to buy exactly one of each type of component.
The problem is which components to buy. As you all know, the quality of a computer is equal to the quality of its weakest component. Therefore, you want to maximize the quality of the component with the lowest quality, while not exceeding your budget.
To make the ideal computer for your needs, you decide to buy separate components and assemble the computer yourself. You need to buy exactly one of each type of component.
The problem is which components to buy. As you all know, the quality of a computer is equal to the quality of its weakest component. Therefore, you want to maximize the quality of the component with the lowest quality, while not exceeding your budget.
Input
On the first line one positive number: the number of testcases, at most 100. After that per testcase:
One line with two integers: 1 ≤ n ≤ 1 000, the number of available components and 1 ≤ b ≤ 1 000 000 000, your budget.
n lines in the following format: “type name price quality”, where type is a string with the type of the component, name is a string with the unique name of the component, price is an integer (0 ≤ price ≤ 1 000 000) which represents the price of the component and quality is an integer (0 ≤ quality ≤ 1 000 000 000) which represents the quality of the component (higher is better). The strings contain only letters, digits and underscores and have a maximal length of 20 characters.
One line with two integers: 1 ≤ n ≤ 1 000, the number of available components and 1 ≤ b ≤ 1 000 000 000, your budget.
n lines in the following format: “type name price quality”, where type is a string with the type of the component, name is a string with the unique name of the component, price is an integer (0 ≤ price ≤ 1 000 000) which represents the price of the component and quality is an integer (0 ≤ quality ≤ 1 000 000 000) which represents the quality of the component (higher is better). The strings contain only letters, digits and underscores and have a maximal length of 20 characters.
Output
Per testcase:
One line with one integer: the maximal possible quality.
One line with one integer: the maximal possible quality.
Sample Input
118 800processor 3500_MHz 66 5processor 4200_MHz 103 7processor 5000_MHz 156 9processor 6000_MHz 219 12memory 1_GB 35 3memory 2_GB 88 6memory 4_GB 170 12mainbord all_onboard 52 10harddisk 250_GB 54 10harddisk 500_FB 99 12casing midi 36 10monitor 17_inch 157 5monitor 19_inch 175 7monitor 20_inch 210 9monitor 22_inch 293 12mouse cordless_optical 18 12mouse microsoft 30 9keyboard office 4 10
Sample Output
9先将这些数据按类型存在相邻的位置,用一个数组记下每个范围;然后用MIN记下最小的qua,用MAX记下最大的MAX;mid=(MIN+MAX)>>1;然后再每个范围内判断这个值是否满足判断这个值用check()函数;满足的话就MIN=mid+1;否则MAX=mid-1;知道MIN<=MAX结束
- HDU 2333 / PKU 3497 (贪心算法+二分)
- hdu 4004 (二分+贪心)
- hdu-5248(贪心+二分)
- 【HDU】5248-序列变换(贪心+二分)
- HDU 1969 pie(贪心+二分)
- 贪心+二分 (分蛋糕)HDU - 1969
- hdu 5248 序列变换(二分+贪心)
- pku 1469 COURSES(二分匹配,匈牙利算法)
- hdu pie(二分+贪心)
- HDU 3650 贪心+二分
- hdu 5248(二分+贪心)
- hdu 3998 Sequence 贪心算法+最长递增子序列+二分查找(好题目)
- HDU 4004 The Frog's Games(基本算法-贪心,搜索-二分)
- hdu 1045 贪心算法、DFS、枚举回溯&二分图
- HDU 2037 (贪心算法)
- HDU 迷瘴(贪心算法)
- 贪心算法(hdu 4442 hdu 3183)
- hdu-1969-Pie(二分+贪心)
- 单反拍摄技巧:利用直方图曝光
- 最小生成树PRIM算法及KRUSKAL算法第四集
- PKU-1002使用java编写用快速排序为何一直Runtime Error 无解 留下问题 以后再看
- Java异常发生时程序的执行顺序
- Oracle字符串如何连接单引号
- HDU 2333 / PKU 3497 (贪心算法+二分)
- Windows host与VirtualBox中linux guest通过数据空间共享文件
- PSP 版本Bookr修改支持中文
- 使用js函数实现的通过输入框中数据的长度来控制光标聚焦位置
- 修改Firefox的磁盘缓存目录
- JQUERY+JSON+Struts 1.3例子
- 剑3资源格式分析(仅用于学习和技术研究)(一)
- 剑3资源格式分析(仅用于学习和技术研究)(二)
- ATM跨行取款手续费比较