hdu 2004 成绩转换

成绩转换

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 21173    Accepted Submission(s): 9308

Problem Description

输入一个百分制的成绩t，将其转换成对应的等级，具体转换规则如下：
90~100为A;
80~89为B;
70~79为C;
60~69为D;
0~59为E;

 

Input

输入数据有多组，每组占一行，由一个整数组成。

 

Output

对于每组输入数据，输出一行。如果输入数据不在0~100范围内，请输出一行：“Score is error!”。

 

Sample Input

5667100123

 

Sample Output

EDAScore is error!
  Online Judge Online Exercise Online Game Online Contests Exercise Author F.A.QHand In HandOnline Acmers Forum | DiscussStatistical Charts Problem ArchiveRealtime Judge StatusAuthors Ranklist   AC Formular Code Challenge STD Contests VIP Contests      Virtual Contests      C/C++ Exams       DIY Contests          killsoon Mail 0(0) Control Panel  Sign Out  用100°的AC热情，挑战39°的高温——加油!  View CodeProblem : 2004 ( 成绩转换 )     Judge Status : AcceptedRunId : 2532676    Language : C    Author : killsoonCode Render Status : Rendered By HDOJ C Code Render Version 0.01 Beta#include<stdio.h>int main(){    int n;    while(scanf("%d",&n)!=EOF)    {        if(n>=0&&n<=59)            printf("E/n");        else if(n>=60&&n<=69)            printf("D/n");        else if(n>=70&&n<=79)            printf("C/n");        else if(n>=80&&n<=89)            printf("B/n");        else if(n>=90&&n<=100)            printf("A/n");        else            printf("Score is error!/n");    }    return 1;}#include<stdio.h>int main(){    int n;    while(scanf("%d",&n)!=EOF)    {        if(n>=0&&n<=59)            printf("E/n");        else if(n>=60&&n<=69)            printf("D/n");        else if(n>=70&&n<=79)            printf("C/n");        else if(n>=80&&n<=89)            printf("B/n");        else if(n>=90&&n<=100)            printf("A/n");        else            printf("Score is error!/n");    }    return 1;}