如何给$.ajax的回调函数传参数?

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    function DeleteSignUpInfo(nSignUpInfoID, nExamSubjectID, nUnifyExamInfoID,nInfoAbleWriter) {
            $.ajax({
                url: "DeleteSignUpInfoHandler.ashx",
                type: "POST",
                dataType: "json",
                data: { "SignUpInfoID": nSignUpInfoID, "ExamSubjectID": nExamSubjectID, "UnifyExamInfoID": nUnifyExamInfoID, "InfoAbelWriter": nInfoAbleWriter },
                success: function (response) { DeleteSignUpInfo_CallBack(response, nSignUpInfoID) },//回调函数传参数
                error: function () { alert("Error!"); }
            });
        }
        function DeleteSignUpInfo_CallBack(response, nSignUpInfoID) {//回调函数
            if (response.IsSuccessful == 1) {
                //服务端删除成功,删除表格数据
                alert(response.Message);
            }
            else {
                alert(response.Message);
            }
        }

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