用xsl实现xml文件超链接一例

来源：互联网发布：lupe fiasco 知乎编辑：程序博客网时间：2024/06/05 07:06

//xml文件

<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="index.xsl"?>

<COMMAND>
<LIST CMD="ACT CELL">file://E:/xml/ACT CELL.xml</LIST>
<LIST CMD="ACT CELLHSDPA">file://E:/xml/ACT CELLHSDPA.xml</LIST>
<LIST CMD="ACT CELLHSUPA">file://E:/xml/ACT CELLHSUPA.xml</LIST>
<LIST CMD="ADD ABLMSG">file://E:/xml/ADD ABLMSG.xml</LIST>
</COMMAND>

//xsl文件

<?xml version="1.0" encoding="gb2312"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl">

<xsl:template match="/">
<HTML><HEAD><TITLE>COMMAND INDEX</TITLE></HEAD>
<BODY>
<h2>COMMAND INDEX</h2>

<xsl:apply-templates select="COMMAND/LIST"/>

</BODY>
</HTML>
</xsl:template>

<xsl:template match="COMMAND/LIST">
<TABLE Border="1" cellspacing="0" class= "GridStyle" rules="all" id= "Grid_Fact" style="border-

color:#009999;width:863px;border-collapse:collapse;table-LAYOUT:fixed;word-wrap:break-word;word-break:break-all">
<tr>
    <td>
      <xsl:value-of select="@CMD"/>
    </td>

</xsl:stylesheet>