从zip 文件中找文件名含有某些字符串的文件/已经所含文件中含有某个字符串的文件//grep

0. 在非zip文件中查找含有某个字符串的文件:

grep -ir '200880288193'  dd/

 

grep -r  'matching str' path

 

1.zip file 中文件名含有"ABC" 的文件 ：

find . -name '*.zip' -exec grep -qi 'ABC' {} /; -exec echo {} /;

2.ｚｉｐ　ｆｉｌｅ　中的文件内容中含有字符串ＡＢＣＤＥＦ的文件：

for file in *.zip; do if unzip -p $file | strings | grep "ＡＢＣＤＥＦ" > /dev/null; then echo $file; fi; done

 

note： unzip -p

 -p     extract  files  to pipe (stdout).  Nothing but the file data is sent to stdout, and the files are always extracted in binary format, just as they are stored (no conversions).

 

grep -qi

-i, --ignore-case
      Ignore case distinctions in both the PATTERN and the input files.

 

 -q, --quiet, --silent
         Quiet;  do  not  write anything to standard output.  Exit immediately with zero status if any match is found, even if an error was detected.Also see the -s or --no-messages option.

 

 -R, -r, --recursive
          Read all files under each directory, recursively; this is equivalent to the -d recurse option.

 

 

another try (almost same):

 

#!/bin/su$searchstring=$1for zipfile in *.zipdo  unzip -qq -l $zipfile | awk '{ print $4 }' | while read file  do    if unzip -p $zipfile $file | grep $searchstring > /dev/null    then      echo "$zipfile / $file"    fi  donedone