度分秒解析……

来源：互联网发布：三国志13pk诸葛亮数据编辑：程序博客网时间：2024/05/16 12:49

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下面是一个运用，看看有用哦：

下列数据为纬度，格式为，度数和分数为1位或者两位，秒的整数部分最大为两位
分别为13度、18分、27.54秒，13度7分9.96秒，6度42分45.67秒，请问怎样读取这些数值
？

131827.54
13 7 9.96
64245.67
#include <stdio.h>
#include <stdlib.h>
int main()
{
    char str1[]="131827.54";
    char str2[]="13 7 9.96";
    char str3[]="64245.67 ";

    int degree,min;
    float sec;

    sscanf(str1,"%2d%2d%5f",&degree,&min,&sec);
    printf("%2d%2d%5.2f/n",degree,min,sec);

    sscanf(str2,"%2d%2d%5f",&degree,&min,&sec);
    printf("%2d%2d%5.2f/n",degree,min,sec);

    sscanf(str3,"%2d%2d%5f",&degree,&min,&sec);
    printf("%2d%2d%5.2f/n",degree,min,sec);

    return 0;
}
写个循环看看

#include <stdio.h>
#define N 10000

int main()
{
    int degree[N],min[N];
    float sec[N];
    int i;

    FILE *file=fopen("data.txt","r");

    for(i=0;i<N;i++)
    {
        fscanf(file,"%2d%2d%5f",&degree[i],&min[i],&sec[i]);
        printf("%2d%2d%5.2f/n",degree[i],min[i],sec[i]);
    }

    fclose(file);
    return 0;
}