给定一个节点指针 删除单链中当前结点

思想：把元素往前移，删除最后一个结点

 

struct List{ int data; struct List* next;};bool DeleteContent(List* p){ if(p->next == NULL) return false; while(p->next->next != NULL) { p->data = p->next->data; p = p ->next; } p->data = p->next->data; p->next = NULL; return true;}void main(){ List* pHeader = new List; pHeader->next = NULL; for(int i=5; i>0; i--) { List* elem = new List; elem->data = i; elem->next = pHeader->next; pHeader->next = elem; } List *p = pHeader->next->next; DeleteContent(p);}