script不刷新页面的联动

来源：互联网发布：js动态生成树形菜单编辑：程序博客网时间：2024/05/20 12:25

<asp:DropDownList ID="type1" runat="server" CssClass="tfont" onchange="link(this.id);" </asp:DropDownList>

       <%-- 大小类--%>
        <script>
                    function link(id)
                    {
                        var obj = document.getElementById(id);
                        var obj1 = document.getElementById('type2');
                        var name = "";
                        for(i = 0 ; i < obj.options.length ; i++ )
                        {
                            if(obj.options[i].selected)
                            {
                                name = obj.options[i].value;
                            }
                        }

                        var names = bargain_class.link(name).value.split(',');

                        var obj1_count = obj1.options.length
                        for (i = 0 ; i < obj1_count ; i++)
                        {
                            obj1.options.remove(0);
                        }
                        for (i = 0 ; i < names.length ; i ++ )
                        {
                            option1 = document.createElement("option");
                            option1.innerHTML = names[i];
                            obj1.appendChild(option1);
                        }

                       // alert(names);
                    }

</script>

//后台代码

AjaxPro.Utility.RegisterTypeForAjax(typeof(bargain_class)); //本页页面名

    //===============================ajax调用=====================================
    [AjaxPro.AjaxMethod]
    public string link(string name)
    {
        string text = "";
        string sql = "select name from Management_products_class where pid='" + name + "'";
        DataTable dt = LinkSql.conn(sql);

        for (int i = 0; i < dt.Rows.Count; i++)
        {
            if (text == "")
            {
                text = dt.Rows[i]["name"].ToString();
            }
            else
            {
                text += "," + dt.Rows[i]["name"].ToString();
            }
        }

return text;

}