FOJ1303——Calendar

来源：互联网发布：会员注册页面html源码编辑：程序博客网时间：2024/04/29 00:49

题意：随便给出一个整数，输出其年月日&&星期，从2000年1.1开始算起：

#include<stdio.h>char *name[] = { "Monday", "Tuesday", "Wednesday","Thursday", "Friday", "Saturday", "Sunday" };int time1[15]={31,28,31,30,31,30,31,31,30,31,30,31};int time2[15]={31,29,31,30,31,30,31,31,30,31,30,31};bool find(int a){if((a%100!=0&&a%4==0)||a%400==0)return true;return false;}int main(void){int d, m, y, a,n,l,yu,i,n1;while(scanf("%d",&n)!=EOF){if(n==-1)break;n1=n;y=2000;while(n>364){if(!find(y)){n-=365;y++;}else {if(n>365){ n-=366;y++;}else break;}}m=1;d=1;if(find(y)){for(i=0;n-time2[i]>=0;i++){n-=time2[i];}m+=i;d+=n;}else{for(i=0;n-time1[i]>=0;i++){n-=time1[i];}m+=i;d+=n;}printf("%d-%02d-%02d ",y,m,d);/*if (m == 1 || m == 2) { m += 12; y--; }if ((y < 1752) || (y == 1752 && m < 9) ||(y == 1752 && m == 9 && d < 3))a = (d + 2*m + 3*(m+1)/5 + y + y/4 +5) % 7;elsea = (d + 2*m + 3*(m+1)/5 + y + y/4 - y/100 + y/400)%7;printf("%s/n", name[a]);*///根据年月日计算星期char week[7][10]={"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};i=(n1%7+6)%7; puts(week[i]);//根据年计算星期}return 0;}