ZJU-2722

 

算对数，然后取最小的大于结果的整数。
可以用math库函数，也可以自己算，后者要注意对1应该输出0，不战而胜。

狂无聊，两个答案都给出

//2008-01-01 15:57:47 Accepted 2722 C++ 00:00.00 396K#include<stdio.h>#include<math.h>int main(){ unsigned long n; while((scanf("%ld",&n)!=EOF) && n!=0) printf("%ld/n",(long)ceil((double)log(n)/log(2))); return 0;}

＝＝＝＝＝＝＝＝＝＝程序间的华丽分隔线＝＝＝＝＝＝＝＝＝＝

//2008-01-01 16:06:43 Accepted 2722 C++ 00:00.00 392K#include<stdio.h>unsigned long roundnum(unsigned long n){ if(n==1) return 0; unsigned long re=0,mu=1; long le=2; while(le>0) { mu *= 2; le = n - mu; re++; } return re;}int main(){ unsigned long n; while((scanf("%ld",&n)!=EOF) && n!=0) { printf("%ld/n",roundnum(n)); } return 0;}