UVa OJ 113-Power of Cryptography

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double的强大：

{ Author:wzx961008 Problem:UVa 11461-Square Numbers Verdict:Accepted Language:PASCAL Run Time:0.028s Submission Date:2011-02-11 05:31:21}uses math;var n,p:double;begin while not eof do begin readln(n); readln(p); writeln(power(p,1/n):0:0); end;end.

UVa OJ 113-Power of Cryptography
UVa 113 Power of Cryptography
uva 113Power of Cryptography
uva 113 Power of Cryptography
UVA 113 - Power of Cryptography
uva 113 - Power of Cryptography
UVa 113 - Power of Cryptography
UVA 113 - Power of Cryptography
UVa 113Power of Cryptography
UVa 113: Power of Cryptography
uva 113 - Power of Cryptography
UVA 113 Power of Cryptography
uva 113 Power of Cryptography
UVA 113 Power of Cryptography
uva - 113 - Power of Cryptography
uva 113 power of Cryptography
UVa 113 - Power of Cryptography
uva 113 - Power of Cryptography
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UVa OJ 113-Power of Cryptography
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