数组2

来源：互联网发布：java编程培训班编辑：程序博客网时间：2024/04/29 07:43

   string s = "";
            string[] names={};

            for (int i = 0; i < names.Length-1; i++)
            {s=s+names[i]+"";
            }
            if (names.Length > 0)//如果没有这句话，那么字符串数组长度为0的时候就会有问题了
            {
                s = s + names[names.Length - 1];
            }
            Console.WriteLine(s);
                Console.ReadKey();

注意声明变量的使用范围，for循环的i只用于本for循环

int[] values = { 30, 15, -5, 199 };
            string[] names = new string[values.Length];
            for (int i = 0; i < values.Length; i++)
            {
                names[i] = Convert.ToString(values[i]);//此处讲数字转换后的字符串数组找一个names数组接着它，要不然就白转换了




            }
            for (int i = 0; i < names.Length; i++)
            {
                Console.WriteLine(names[i]);
            }

                Console.ReadKey();

交换两个变量采用找一个中间值，存储

int i1=10;

int i2=130;

int temp=i 1;

i1=i2;

i2=temp;

            string[] names = { "30","32","53","23"};
            for (int i = 0; i < names.Length/2; i++)
            {
                string temp = names[i];
                names[i] = names[names.Length - 1 - i];
                names[names.Length - 1 - i] = temp;

            } for (int i = 0; i < names.Length; i++)
            {
                Console.WriteLine(names[i]);
            }

函数： int[] values = { 3, 5, 3, 9 };
            int sum = Sum(values);
            Console.WriteLine(sum);
            Console.ReadKey();

        }
        static int Sum(int[] values)
        {
            int sum = 0;
            foreach (int i in values)
            {
                sum = sum + i;
            }
            return sum;