[原创] C语言位运算和bit位操作程序题目答案 -- 谭浩强C语言习题答案

    这两天复习RenMian给我留下谭浩强的C语言教程，温故而知新，夯实基础知识，

    把谭浩强版C语言的第十二章《位运算》的书复习后把所有的编程习题做了一遍，贴出来激励自己一下，也希望有用的同学可以参考，时间和水平有限，不足之处，恳请读者批评指正

 

    第十二章《位运算》答案如下

 

inc/testBits.h

 

unsigned short getbits(unsigned short value, int n1, int n2){ unsigned short usRet = 0, usTemp = 0, usMask = 0; usTemp = value >> n1; usMask = ~( ~0 << (n2 - n1 + 1)); usRet = usTemp & usMask; return usRet;}short getComplement(short n){ short sRet = 0; if (n >= 0) { sRet = n; } else { sRet = -n; sRet = ~sRet; sRet = sRet + 1; } return sRet;}unsigned short move(unsigned short value, int n){ unsigned short usTemp = 0, usDest = 0; assert(n != 0); if (n > 0) { usTemp = value << (16 -n); usDest = value >> n; } else { n = -n; usTemp = value >> (16 - n); usDest = value << n; } usDest = usDest | usTemp; return usDest;}int test_12_1(){ unsigned short usRet = 0; usRet = getbits(0x83BD, 4, 7); if (usRet == 0xB) { printf("Test_12_1 Passed! /r/n"); return 0; } return 1;}int test_12_2(){ int ite = 0, iRet = 0; unsigned short usDest = 0, usSrc = 0xFFFF, usMask = 0; for(ite = 0; ite < 16; ite += 2) { usMask = 1 << ite; usDest = usDest | (usSrc & usMask); } if (usDest == 0x5555) { printf("Test_12_2 Passed! /r/n"); return 0; } return 1;}int test_12_4(){ unsigned short usDest1 = 0, usDest2 = 0, usSrc = 0xFFF7; usDest1 = move(0xFFF7, 4); usDest2 = move(0xFFF7, -4); if (usDest1 == 0x7FFF && usDest2 == 0xFF7F) { printf("Test_12_4 Passed! /r/n"); return 0; } return 1;}int test_12_5(){ short sDest = 0, sSrc = -10; sDest = getComplement(sSrc); if (sDest == 0xFFFFFFF6) { printf("Test_12_5 Passed! /r/n"); return 0; } return 1;}int testBits(){ int iRet = 0; iRet += test_12_1(); iRet += test_12_2(); iRet += test_12_4(); iRet += test_12_5(); return iRet;}

 

src/main.cc

 

#include <stdio.h>#include <stdlib.h>#include <assert.h>#include "../inc/testFile.h"#include "../inc/testBits.h"int main(){ int iRet = 0;#if 0 iRet += testFile(); assert(iRet == 0);#endif iRet += testBits(); assert(iRet == 0); return 0;}