EditGrid可编辑表格的示例（json发送到后台）

来源：互联网发布：表添加字段sql语句编辑：程序博客网时间：2024/04/30 02:40

参考网站： http://www.blogjava.net/algz/articles/213006.html

前台代码：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head> <title></title> <link href="extS/resources/css/ext-all.css" mce_href="extS/resources/css/ext-all.css" rel="stylesheet" type="text/css" /> <mce:script src="extS/ext-base.js" mce_src="extS/ext-base.js" type="text/javascript"></mce:script> <mce:script src="extS/ext-all.js" mce_src="extS/ext-all.js" type="text/javascript"></mce:script> <mce:script src="extS/ext-lang-zh_CN.js" mce_src="extS/ext-lang-zh_CN.js" type="text/javascript"></mce:script> <mce:script type="text/javascript"></mce:script></head><body> <div id="example-grid"> </div></body></html>

后台代码：

using System;using System.Collections.Generic;using System.Linq;using System.Web;using System.Web.Script.Serialization;namespace WebApplication_study.EXT_DB{ /// <summary> /// Summary description for EditGridAjax /// </summary> public class EditGridAjax : IHttpHandler { public void ProcessRequest(HttpContext context) { context.Response.ContentType = "text/plain"; string json = context.Request.Form["UpdateInfo"].ToString();//获取json字符串 List<student> result = JosnDeserialize<List<student>>(json, null);//通过泛型进行反序列化，解析成list foreach (var item in result )//进行逻辑处理，数据库交互 { student s = item; } context.Response.Write("successful"); } public bool IsReusable { get { return false; } } public class student { public string ID { set; get; } public string name { set; get; } public string sex { get; set; } public string addtime { get; set; } } /// <summary> /// 将指定的 JSON 字符串转换为 T 类型的对象。 /// </summary> /// <typeparam name="T">所生成对象的类型。</typeparam> /// <param name="input">要进行反序列化的 JSON 字符串。</param> /// <param name="def">反序列化失败时返回的默认值。(null)</param> /// <returns>反序列化的对象。</returns> public static T JosnDeserialize<T>(string input, T def) { if (string.IsNullOrEmpty(input)) return def; try { JavaScriptSerializer jsSerializer = new JavaScriptSerializer(); return jsSerializer.Deserialize<T>(input); } catch (InvalidOperationException) { return def; } } /// <summary> /// 将对象转换为 JSON 字符串。 /// </summary> /// <param name="obj">要序列化的对象。</param> /// <returns>序列化的 JSON 字符串。</returns> public static string JsonSerialize(object obj) { JavaScriptSerializer jsSerializer = new JavaScriptSerializer(); return jsSerializer.Serialize(obj); } }}