让c++与lua互操作

首先封装一个类lua_wrapper，供需要向lua暴露接口的c++类继承：

extern "C" {#include <lua.h>#include <lua.hpp>#include <lauxlib.h>#include <luaconf.h>#include <lualib.h>}class lua_wrapper{typedef int (*fun_cpp_api)(lua_State* luaState);private:static lua_State *s_lua_ptr;map<string, fun_cpp_api> m_map_api;public:static bool lua_base_init(){if (s_lua_ptr = NULL) {s_lua_ptr = lua_open();if (s_lua_ptr != NULL) {luaopen_base(s_lua_ptr);luaopen_table(s_lua_ptr);luaopen_string(s_lua_ptr);luaopen_math(s_lua_ptr);return true;}}return false;}int Call(const string fun_name, lua_State* luaState){map<string, fun_cpp_api>::const_iterator iter =m_map_api.find(fun_name);if (iter == m_map_api.end()) {return -1;}return (iter->second)(luaState);}#define API_ADD_FUN(fun) do { /m_map_api[#fun] = fun; /setfield(#fun, fun); /} while(0)#define BEGIN_FUNCTION_MAP(x) /lua_newtable(s_lua_ptr); /API_ADD_FUN(Call); /API_ADD_FUN(AttachListener); /API_ADD_FUN(DetachListener); }; 

详细说明：

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