Web Services类型请求中替换XML格式的节点值的方法

来源：互联网发布：初级数据分析师面试题编辑：程序博客网时间：2024/05/22 03:18

LoadRunner在Web Services请求的XML格式串中需要参数化某一个参数，以前的做法是使用string类函数拼出新的XML串，但经过深入的学习lr_save_string（）和lr_eval_string（）两个函数，发现有更简洁的方法，如下：

使用函数lr_save_string()与lr_eval_string()完成转换：

lr_save_string( lr_eval_string("{NewParam}"),"username");

其中{NewParam}为使用lr自带的参数化而成的参数。

然后，传入username：

例如：

soap_request("StepName=Login",

"URL=http://10.0.16.221/i6P/i6Service/WinLoginService.asmx",

"SOAPEnvelope=<?xml version=/"1.0/" encoding=/"GBK/" standalone=/"no/"?"

"><soap:Envelope xmlns:xsd=/"http://www.w3.org/2001/XMLSchema/" xmlns"

":xsi=/"http://www.w3.org/2001/XMLSchema-instance/" xmlns:soap=/"http:/"

"/schemas.xmlsoap.org/soap/envelope//"><soap:Body><Login xmlns=/"http:/"

"/tempuri.org//"><userConnectString>lers14t;5a8i2ix3b4g7=318p="

"j0t030c2jyio1r9i0nid3tt4xp89ocaNv8yt0ycahce0ol9nwen4ieh0cxoth5t8vylepx"

"lecp=jesI8qgel20cttlm3iaee=bn19tcn;yrsmheyorm0v9qe51rxs="

"ja1bw0eu.2e0b5.301;s6r3.bd2qp22s136;opdeDa9wt51aembxxarjsweelb="

"r6nttgrS0s50920541ih;equdIs5mer2r62 e=itodjl=.0s5kaw4;"

"rtp8Na0bs6wsgmwssoo6r5pd9i=kr1pq2gu3s24hj5ve6ykvxql6il="

"nandI62.ua7hc0kkvbeCnsmpv;lyy3ptgsseaxgryy18b8o8rt4v0e2y2wibrgoygleh9="

"dmehh9020t3u.i2jd2ixgtsu26a1yxxbpaa10000001000010010000001000000000000"

"000000100000000110000010000110000100000000000000</userConnectString>"

"<curAcc>0001</curAcc><logid>{username}</logid><passWord/></Login></soap"

":Body></soap:Envelope>",

"Snapshot=t35.inf",

"ResponseParam=response",

LAST);