Check if the string has unique char.
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The code is using additional space to store if the char is already contained in the string or not.
现在这段code和之前的remove duplicate char in a string其实是一样的。
另外现在的这段code仅限于ascii,不适用于UTF。因为UTF可能是16位的。
Will post another snipet of code which doesn't use any other space.
以上这个方法是O(n*n)时间复杂度
后来书上查到一个方法是O(nlog n)的方法,因为用了快速排序,当然修改了一把
其中用到的partition方法是快速排序中标准的方法
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