android如何访问webservices (wsdl 或 asmx)

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下文来自:

 

http://www.ibm.com/developerworks/webservices/library/ws-android/index.html    ----- (主要讲解 wsdl格式的访问)

http://blog.163.com/wkai2009@126/blog/static/120177812201071161820/

 

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android如何访问webservices

 


在DevDiv中我提过这个问题,非常感谢各位朋友给我提供的资料。经过整理测试现在我整理出来给大家共享
android通过KSOP2访问asmx和wsdl
1.下载ksoap2-android-assembly-2.4-jar-with-dependencies.jar(138m).并加载到工程libraries中。
2.由于android默认是禁用soket所以在开始之前需要修改AndroidManifest.xml。添加:<uses-permission android:name="android.permission.INTERNET" />
3.导入包:
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
   3.1wsdl的连接:
    SoapObject request = new SoapObject("http://172.16.2.53:8080/j2me_webservice1/services/hello", "getHello");
      request.addProperty( "name", "name" );
      SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
      envelope.bodyOut = request;  
      HttpTransportSE ht = new HttpTransportSE("http://172.16.2.53:8080/j2me_webservice1/services/hello?wsdl");
      try
     {
       ht.call(null, envelope);
       Object Response = envelope.getResult();
      MessageBox(Toast.LENGTH_SHORT,Response.toString());
     }
    catch(Exception ex)
    {
    MessageBox(Toast.LENGTH_SHORT,ex.getMessage().toString());
    }
3.2 asmx连接
String nameSpace = "http://tempuri.org/";
        String serviceURL = "http://172.16.2.40/FullerTon/WebService.asmx";
        String methodName = "CheckUer";
        String soapAction = "http://tempuri.org/CheckUer";
        SoapObject request = new SoapObject(nameSpace, methodName);
        
        request.addProperty("UserNum", "111");
        request.addProperty("UserPwd", "");
        request.addProperty("PdaNum", "111");
        request.addProperty("SyncNum", "5.0");
        
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.bodyOut = request;
        envelope.dotNet=true;
        HttpTransportSE ht = new HttpTransportSE(serviceURL);
        ht.debug = true;
        try {
            ht.call(soapAction, envelope);
            if (envelope.getResponse() != null) {
                return envelope.getResponse().toString();
            } else {
                return "null";
            }
        } catch (Exception e) {
            e.printStackTrace();
            return "err";
        }
说明:其中nameSpace,soapAction 。用浏览器打开的你的webservice 中都可以找到

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