2007年第8期编程点将台

来源：互联网发布：日本食玩包邮淘宝编辑：程序博客网时间：2024/05/16 13:14

将1到1000的阿拉伯数字转换为罗马数字

源程序如下所示：
#include<stdio.h>
char c[3][3]={{'I','V','X'},{'X','L','C'},{'C','D','M'}};

void convert(int temp,int i){

switch(temp){
case 0:
  break;
case 1:
  printf("%c",c[2-i][0]);
  break;
case 2:
  printf("%c%c",c[2-i][0],c[2-i][0]);
  break;
case 3:
  printf("%c%c%c",c[2-i][0],c[2-i][0],c[2-i][0]);
  break;
case 4:
  printf("%c%c",c[2-i][0],c[2-i][1]);
  break;
case 5:
  printf("%c",c[2-i][1]);
  break;
case 6:
  printf("%c%c",c[2-i][1],c[2-i][0]);
  break;
case 7:
  printf("%c%c%c",c[2-i][1],c[2-i][0],c[2-i][0]);
  break;
case 8:
  printf("%c%c%c%c",c[2-i][1],c[2-i][0],c[2-i][0],c[2-i][0]);
  break;
    default:
  printf("%c%c",c[2-i][0],c[2-i][2]);
  break;
}
}

main()
{
int i,input,n,temp;
int k[3]={0,0,0};
int m[3]={100,10,1};
printf("Input a integer from 0 to 1000:");
scanf("%d",&input);
n=input;
if(n<0||n>1000)
  printf("Please input a integer between 0 and 1000/n");
else if(n==1000)
  printf(" Bingo! 1000 convert to Roman numeral is ");

else{
  printf(" Bingo! %d convert to Roman numeral is ",n);
  for(i=0;i<3;i++){
   k[i]=(n-100*k[0]-10*k[1])/m[i];
   temp=k[i];
   convert(temp,i);
  }
}
printf("/n");
}