Inside the C++ Object Model 学习笔记 第四章 函数语意学 测试代码 乱写的

 #include<iostream>using namespace std;class A{public:virtual void fun1(){cout<<"A::fun1"<<endl;}virtual void fun2(){cout<<"A::fun2"<<endl;}virtual void fun3(){cout<<"A::fun3"<<endl;}};class A1:public A{public:virtual void fun1(){cout<<"A1::fun1"<<endl;}};class A2:public A{public:virtual void fun2(){cout<<"A2::fun2"<<endl;}virtual void fun3(){cout<<"A2::fun3"<<endl;}};class B :public A1,public A2{public:virtual void fun4(){cout<<"B::fun4"<<endl;}};int main(int argc, char* argv[]){A1 a1; typedef int Fun;cout<<"A1虚函数表的地址为:"<<(int *)(&a1)<<endl; cout<<"A1第一个虚函数的地址为:"<<(int *) *(int *)(&a1)<<endl; Fun fun1,fun2,fun3,fun4;fun1=( Fun) ( *(int *) *(int *)(&a1));a1.fun1();fun2=(Fun) (* ((int *) *(int *)(&a1)+1));a1.fun2();fun3=(Fun) (* ((int *) *(int *)(&a1)+2));a1.fun3();A2 a2;cout<<"A2虚函数表的地址为:"<<(int *)(&a2)<<endl; cout<<"A2第一个虚函数的地址为:"<<(int *) *(int *)(&a2)<<endl; fun1=( Fun) ( *(int *) *(int *)(&a2));a2.fun1();fun2=(Fun) (* ((int *) *(int *)(&a2)+1));a2.fun2();fun3=(Fun) (* ((int *) *(int *)(&a2)+2));a2.fun3();B b;cout<<"B的第一个虚函数表的地址为:"<<(int *)(&b)<<endl; cout<<"B的第一个虚函数表的第一个虚函数的地址为:"<<(int *) *(int *)(&b)<<endl; fun1=( Fun) ( *(int *) *(int *)(&b)); cout<<fun1<<endl;fun2=(Fun) (* ((int *) *(int *)(&b)+1));cout<<fun2<<endl;fun3=(Fun) (* ((int *) *(int *)(&b)+2));cout<<fun3<<endl;fun4=(Fun) (* ((int *) *(int *)(&b)+3));cout<<fun4<<endl; cout<<"B的第二个虚函数表的地址为:"<<(int *)(&b)+1<<endl; cout<<"B的第二个虚函数表的第一个虚函数的地址为:"<<(int *) *((int *)(&b)+1)<<endl; fun1=( Fun) ( *(int *) *((int *)(&b)+1)); cout<<fun1<<endl;fun2=(Fun) (* ((int *) *((int *)(&b)+1)+1));cout<<fun2<<endl;fun3=(Fun) (* ((int *) *((int *)(&b)+1)+2));cout<<fun3<<endl;char ch;while (1){cin>>ch;}return 0;}

主要就是写了 多重继承下的东西 结果如下