无第三方交换2个数

http://blog.csdn.net/ljzcome/archive/2006/01/09/574158.aspx

 

#include "stdafx.h"#include<iostream>using namespace std;int main(int argc, char* argv[]){ int i=60; int j=50; i^=j; j^=i; i^=j; printf("i=%d/n",i); printf("j=%d/n",j); while(1); return 0;} #include "stdafx.h"#include<iostream>using namespace std;int main(int argc, char* argv[]){ int i=60; int j=50;i = (i+j)-(j=i);//从右边开始的，奇怪printf("i=%d/n",i); printf("j=%d/n",j); while(1); return 0;}