poj 1131Octal Fractions

/*解题报告：(0.75)8 = (7*8-1 * 5*8-2) = (0.953125)10 其中负号代理多少次方(0.75)8 = ((5/8 + 7)/8)*/#include <iostream>#include <cstring>using namespace std;const int MAX = 100;char szOctal[MAX];char szDest[MAX];int main(){int i, j;int nNum, nTemp;int nIndex;while(cin>>szOctal){memset(szDest, 0, sizeof(szDest));nIndex = 0;for(i=strlen(szOctal)-1; i>1; i--){nNum = szOctal[i] - '0';//实现小数的大数除（本题为除8的大数除法）for(j=0; j<nIndex || nNum; j++){nTemp = nNum * 10 + (j<nIndex ? szDest[j] - '0' : 0);szDest[j] = nTemp/8 + '0';nNum = nTemp%8;}nIndex = j;}szDest[j] = '/0';cout<<szOctal<<" [8] = 0."<<szDest<<" [10]"<<endl;}return 0;}