.NET中使用Protobuffer 实现序列化和反序列化

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.NET中使用Protobuffer实现序列化和反序列化

 

1.       到官方下载protobuf-net.dll,官方地址:http://code.google.com/p/protobuf-net/

2.      建一个控制台应用程序

3.      添加类库:protobuf-net.dll到应用程序。

示例代码:

 

准备一个要测试的实体类(注意类和方法都要加上protoBuffer序列化的特性):

 

 

 [ProtoContract]    public class Student    {        [ProtoMember(1)]        public intStudentId { get; set; }        [ProtoMember(2)]        public stringName { get; set; }        [ProtoMember(3)]        public stringClassName { get; set; }    }

 

然后对这个类进行序列化反序列化

 

 

 

using System;using System.Collections.Generic;using System.Linq;using System.Text;using ProtoBuf;using ProtoBufferDemo.Entity;using System.IO; namespace ProtoBufferDemo{   class Program   {        private const string TestPath = @"D:/1.txt";        static void Main(string[] args)        {            ////////////////////////序列化//////////////////////////////             Student stu = new Student()            {                StudentId = 1,                Name = "zhangsan",                ClassName = "classOne"            };             if (!File.Exists(TestPath))            {               FileStream fs = File.Create(TestPath,1024, FileOptions.Asynchronous);               fs.Dispose();            }             Console.WriteLine("开始序列化并导出到文件...");            using (Stream s = new FileStream(TestPath,FileMode.Open ,FileAccess.ReadWrite))            {                Serializer.Serialize<Student>(s, stu);                s.Close();            }            Console.WriteLine("序列化完毕");             //////////////////////反序列化////////////////////////////             Console.WriteLine("反序列化并输出...");            using (Stream s = new FileStream(TestPath,FileMode.Open))            {                Student st = Serializer.Deserialize<Student>(s);                Console.WriteLine("studentName:"+ stu.Name + "/r/n" +                                  "studentId:"+ stu.StudentId + "/r/n" +                                  "className:" + stu.ClassName);                s.Close();            }             Console.Read();        }   }}


 

现在考虑一下多个实体的情况,测试一下序列化一个集合

 

class Program   {        private const string TestPath = @"D:/1.txt";        static void Main(string[] args)        {            ////////////////////////序列化//////////////////////////////             List<Student> stu = new List<Student>()            {                new Student(){                StudentId = 1,                Name = "zhangsan",                ClassName = "classOne"},                 new Student(){StudentId = 2,                Name = "lisi",                ClassName = "classTwo"}            };             if (!File.Exists(TestPath))            {                FileStream fs = File.Create(TestPath,1024, FileOptions.Asynchronous);                fs.Dispose();            }             Console.WriteLine("开始序列化并导出文件...");            using (Stream s = new FileStream(TestPath,FileMode.Open, FileAccess.ReadWrite))            {                Serializer.Serialize<List<Student>>(s,stu);                s.Close();            }            Console.WriteLine("序列化完毕");             //////////////////////反序列化////////////////////////////             Console.WriteLine("反序列化并输出...");            using (Stream s = new FileStream(TestPath,FileMode.Open))            {                List<Student> sl = Serializer.Deserialize<List<Student>>(s);                 foreach (var student in sl)                {                    Console.WriteLine("studentName:"+ student.Name + "/r/n" +                                "studentId:" + student.StudentId + "/r/n" +                                "class Name:" + student.ClassName);                }                               s.Close();            }             Console.Read();        }   }


 

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