(2011.07.08)编程练习_07.08_处理数组和结构的函数.cpp 输出结果有问题。

// 编程练习_07.08_处理数组和结构的函数.cpp


/******************************************************************
8.这个练习让您编写处理数组和结构的函数。下面是程序的框架，
请提供其中描述的函数，以完成该程序。


#include <iostream>
using namespace std;


const int SLEN = 30;
struct student {
char fullname[SLEN];
char hobby[SLEN];
int ooplevel;
};
// getinfo() has two arguments: a pointer to the first element of 
// an array of student structures and an int representing the 
// number of elements of the array. The function solicits and
// stores data about students. It terminates input upon filling
// the array or upon encoutering a blank line for the student
// name. The function returns the actual namber of array elements
// filled.
int getinfo(student pa[], int n);


// display1()takes a student structure as an argument
// and displays its contents
void display1(student st);


// display2()takes the address of student structure as an 
// argument and displays the structure's contents
void display2(const student *ps);


// display3()takes the address of the first element of an array
// of student structures and the number of array elements as


// arrguments and displays the contents of the structures 
void display3(const student pa[], int n);


int main()
{
cout << "Enter class size:";
int class_size;
cin >> class_size;
while(cin.get() != '\n')
continue;


student * ptr_stu = new student [class_size);
int entered = getinfo(ptr_stu, class_size);
for (int i = 0; i < entered; i++)
{
display1(ptr_stu[i]);
display2(&ptr_stu[i]);
}
display3(ptr_stu, entered);
delete[] ptr_stu;
cout << "Done\n";
return 0;
}


*****************************************************************/


#include <iostream>
using namespace std;


const int SLEN = 30;
struct student 
{
char fullname[SLEN];
char hobby[SLEN];
int ooplevel;
};
// getinfo() has two arguments: a pointer to the first element of 
// an array of student structures and an int representing the 
// number of elements of the array. The function solicits and
// stores data about students. It terminates input upon filling
// the array or upon encoutering a blank line for the student
// name. The function returns the actual namber of array elements
// filled.
int getinfo(student pa[], int n);


// display1()takes a student structure as an argument
// and displays its contents
void display1(student st);


// display2()takes the address of student structure as an 
// argument and displays the structure's contents
void display2(const student *ps);


// display3()takes the address of the first element of an array
// of student structures and the number of array elements as


// arrguments and displays the contents of the structures 
void display3(const student pa[], int n);


int main()
{
cout << "Enter class size:";
int class_size;
cin >> class_size;
while(cin.get() != '\n')
continue;


student * ptr_stu = new student [class_size];
int entered = getinfo(ptr_stu, class_size);
for (int i = 0; i < entered; i++)
{
display1(ptr_stu[i]);
display2(&ptr_stu[i]);
}
display3(ptr_stu, entered);
delete[] ptr_stu;
cout << "Done\n";
return 0;
}




// getinfo() has two arguments: a pointer to the first element of 
// an array of student structures and an int representing the 
// number of elements of the array. The function solicits and
// stores data about students. It terminates input upon filling
// the array or upon encoutering a blank line for the student
// name. The function returns the actual namber of array elements
// filled.
int getinfo(student pa[], int n)
{
for (int i = 0; i < n && pa[i-1].fullname == ""; ++i)
{
cout << "Please enter this student's fullname: ";
cin >> pa[i].fullname;
cout << "Please enter this student's hobby: ";
cin >> pa[i].hobby;
cout << "Please enter this student's ooplevel: ";
cin >> pa[i].ooplevel;
}
return i;
}


// display1()takes a student structure as an argument
// and displays its contents
void display1(student st)
{
cout << st.fullname << '\t' << st.hobby << '\t' 
<< st.ooplevel;
}


// display2()takes the address of student structure as an 
// argument and displays the structure's contents
void display2(const student *ps)
{
cout << ps -> fullname << '\t' 
<< ps -> hobby << '\t' 
<< ps -> ooplevel << endl;
}




// display3()takes the address of the first element of an array
// of student structures and the number of array elements as


// arrguments and displays the contents of the structures 
void display3(const student pa[], int n)
{
for (int i = 0; i < n && pa[i-1].fullname == ""; ++i)
{
cout << pa[i].fullname << '\t' ;
cout << pa[i].hobby << '\t' ;
cout << pa[i].ooplevel << endl;
}

}

//  哈哈，终于改正成功了。

// 编程练习_07.08_处理数组和结构的函数.cpp/******************************************************************8.这个练习让您编写处理数组和结构的函数。下面是程序的框架，请提供其中描述的函数，以完成该程序。#include <iostream>using namespace std;const int SLEN = 30;struct student {char fullname[SLEN];char hobby[SLEN];int ooplevel;};// getinfo() has two arguments: a pointer to the first element of // an array of student structures and an int representing the // number of elements of the array. The function solicits and// stores data about students. It terminates input upon filling// the array or upon encoutering a blank line for the student// name. The function returns the actual namber of array elements// filled.int getinfo(student pa[], int n);// display1()takes a student structure as an argument// and displays its contentsvoid display1(student st);// display2()takes the address of student structure as an // argument and displays the structure's contentsvoid display2(const student *ps);// display3()takes the address of the first element of an array// of student structures and the number of array elements as// arrguments and displays the contents of the structures void display3(const student pa[], int n);int main(){cout << "Enter class size:";int class_size;cin >> class_size;while(cin.get() != '\n')continue;student * ptr_stu = new student [class_size);int entered = getinfo(ptr_stu, class_size);for (int i = 0; i < entered; i++){display1(ptr_stu[i]);display2(&ptr_stu[i]);}display3(ptr_stu, entered);delete[] ptr_stu;cout << "Done\n";return 0;}*****************************************************************/#include <iostream>using namespace std;const int SLEN = 30;struct student {char fullname[SLEN];char hobby[SLEN];int ooplevel;};// getinfo() has two arguments: a pointer to the first element of // an array of student structures and an int representing the // number of elements of the array. The function solicits and// stores data about students. It terminates input upon filling// the array or upon encoutering a blank line for the student// name. The function returns the actual namber of array elements// filled.int getinfo(student pa[], int n);// display1()takes a student structure as an argument// and displays its contentsvoid display1(student st);// display2()takes the address of student structure as an // argument and displays the structure's contentsvoid display2(const student *ps);// display3()takes the address of the first element of an array// of student structures and the number of array elements as// arrguments and displays the contents of the structures void display3(const student pa[], int n);int main(){cout << "Enter class size:";int class_size;cin >> class_size;while(cin.get() != '\n')continue;student * ptr_stu = new student [class_size];int entered = getinfo(ptr_stu, class_size);for (int i = 0; i < entered; i++){display1(ptr_stu[i]);display2(&ptr_stu[i]);}display3(ptr_stu, entered);delete[] ptr_stu;cout << "Done\n";cin.get();cin.get();cin.get();return 0;}// getinfo() has two arguments: a pointer to the first element of // an array of student structures and an int representing the // number of elements of the array. The function solicits and// stores data about students. It terminates input upon filling// the array or upon encoutering a blank line for the student// name. The function returns the actual namber of array elements// filled.int getinfo(student pa[], int n){    int i;for (i = 0; i < n ; ++i){cout << "Please enter this student's fullname: ";        int j;cin.get(pa[i].fullname[0]); if (pa[i].fullname[0] == '\n') { break;         }for (j = 1; j < SLEN && (pa[i].fullname[j-1] != '\n'); ++j){ cin.get(pa[i].fullname[j]); pa[i].fullname[j+1] = '\0';}cout << "Please enter this student's hobby: ";cin >> pa[i].hobby;cout << "Please enter this student's ooplevel: ";cin >> pa[i].ooplevel;cin.get();}return i;}// display1()takes a student structure as an argument// and displays its contentsvoid display1(student st){cout << st.fullname << '\t' << st.hobby << '\t' << st.ooplevel << endl;}// display2()takes the address of student structure as an // argument and displays the structure's contentsvoid display2(const student *ps){cout << ps -> fullname << '\t' << ps -> hobby << '\t' << ps -> ooplevel << endl;}// display3()takes the address of the first element of an array// of student structures and the number of array elements as// arrguments and displays the contents of the structures void display3(const student pa[], int n){for (int i = 0; i < n; ++i){if (pa[i].fullname == ""){break;}cout << pa[i].fullname << '\t' ;cout << pa[i].hobby << '\t' ;cout << pa[i].ooplevel << endl;}}