Struts2 与 Ext 整合开发

 最近一直想找一个Struts与Ext整合的一个比较规范的做法，个人觉得必然使用Struts的json，弄了一个晚上，不知道是否在符合大众的规范，配置如下：

Struts2从2.1.7开始便将json整合进去了，从Strtus2的lib包中可以片可以找到，名为struts2-json-plugin-2.x.x.x.jar

将json-plugin放入工程的lib中去后，便可以开始进行开发：

Action：

package com.bjsoft.oa.action.system;import nl.captcha.Captcha;import org.apache.commons.lang.xwork.StringUtils;import com.bjsoft.oa.model.User;import com.bjsoft.oa.service.UserService;import com.opensymphony.xwork2.ActionContext;import com.opensymphony.xwork2.ActionSupport;public class LoginAction extends ActionSupport {private static final long serialVersionUID = 2578893349737621315L;private UserService userService;private User user;private String simpleCaptcha;private boolean success;private String msg;@Overridepublic String execute() throws Exception {success = false;msg = "";Captcha _simpleCaptcha = (Captcha) ActionContext.getContext().getSession().get("simpleCaptcha");if (_simpleCaptcha.isCorrect(simpleCaptcha)) {String _userName = user.getUsername();String _password = user.getPassword();if (!StringUtils.isEmpty(_userName)&& !StringUtils.isEmpty(_password)) {User u = this.userService.getUserByName(_userName);if(u != null){if (StringUtils.equals(u.getPassword(), _password)) {success = true;} else {msg = "密码错误！";}}else{msg = "不存在的用户";}} else {msg = StringUtils.isEmpty(_userName) ? "用户名不能为空" : "密码不能为空";}} else {msg = "验证码错误！";}return super.execute();}public UserService getUserService() {return userService;}public void setUserService(UserService userService) {this.userService = userService;}public User getUser() {return user;}public void setUser(User user) {this.user = user;}public String getSimpleCaptcha() {return simpleCaptcha;}public void setSimpleCaptcha(String simpleCaptcha) {this.simpleCaptcha = simpleCaptcha;}public boolean isSuccess() {return success;}public void setSuccess(boolean success) {this.success = success;}public String getMsg() {return msg;}public void setMsg(String msg) {this.msg = msg;}}

strtus.xml

<struts><package name="login" namespace="/" extends="json-default"><action name="login" class="com.bjsoft.oa.action.system.LoginAction"><result type="json"><param name="includeProperties">success,msg</param></result></action></package></struts>

这里的package一定要继承json-default,并且result type也是要json格式，同时另一个问题是没有参数的json result 将会把action中所有局部变量放在json格式的字符串返回给前端，这样似乎就造成了不必要的浪费，于是有两种解决办法，一种是上面的配置，告诉struts应该包含哪些变量，另一种是告诉struts不应该包含哪些变量，

<!-- Result fragment --><result type="json">  <param name="excludeProperties">    login.password,    studentList.*\.sin  </param></result>

这样就可以了。