ZOJ3121 POJ3488 Arne Saknussemm

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挺简单的模拟题，直接给代码吧

/******************************************************************************* * Author : Neo Fung * Email : neosfung@gmail.com * Last modified : 2011-07-12 16:43 * Filename : ZOJ3121_POJ3488_Arne_Saknussemm.cpp * Description : ZOJ3121 POJ3488 Arne Saknussemm * *****************************************************************************/// ZOJ3121_POJ3488_Arne_Saknussemm.cpp : 定义控制台应用程序的入口点。//#include <stdio.h>#include <iostream>#include <string>#include <vector>#include <map>#include <math.h>#include <algorithm>#include <numeric>#include <functional>using namespace std;int main(void){//ifstream cin("data.txt");char fragments[1001][1001];int n,length;int i,j,flag =1;string str;while(cin>>n){for(i=0;i<n;++i){str.clear();cin>>str;for(j=0;j<str.length();++j)fragments[i][j] = str.at(j);}length = str.length();str.clear();for(j = length-1; j>=0;--j)for(i = n-1;i>=0;--i){if(fragments[i][j] == '_')str += ' ';else if(fragments[i][j] == '\\')str +='\n';elsestr += fragments[i][j];}for (length = str.length()-1;length>=0;--length){if (str.at(length) != ' '){break;}}for(i = 0 ;i<=length;++i){printf("%c",str.at(i));}cout<<endl<<endl;}return 0;}