hoj 1040 As Easy As A+B
来源:互联网 发布:中高级java工程师招聘 编辑:程序博客网 时间:2024/05/17 01:39
很水的题啊..输入数组,将它从小到大排序
用sort()函数就搞定
其实我是想练快排(QuickSort)的...
#include <stdio.h>#include <stdlib.h>#include <string.h>#include <algorithm>using namespace std;int main(){int ncase;int n;int i;int num[1000];scanf("%d" ,&ncase);while( ncase--){scanf("%d", &n);for (i=0; i<n; i++){scanf("%d", &num[i]);}sort(num,num+n);for (i=0; i<n; i++){if (i<n-1){printf("%d ", num[i]);}else if (i == n-1){printf("%d\n",num[i]);}}}system("pause");return 0;}
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