数字翻译器及其实现

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【问题描述】
输入一个正整数N(N最大是4位数),输出它的英文表达。
【样例】
输入:1
输出:one
又输入:12
输出:twelve
右输入:135
输出:one hundred thirty five

思路:1、首先19以内的数字,可以直接输出。。

2、20~~~99以内的数字,整十的整数可以直接输出。否则,除以10输出十位数字,与10取模输出个位数字。

3、100~~~999以内的数字,除以100输出百位数字,与100取模得到一个两位的数字,转到2

4、1000~~~9999以内的数字,除以1000输出千位数字,与1000取模得到一个三位的数字,转到3

完整的实现代码如下:

#include "iostream"using namespace std;char table[20][20]= {"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","ninteen" };char tens[12][20]={"","ten","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninty","hundred","thousand" };void print(int n){if(n >= 0 && n <= 19){cout<<table[n];         //直接输出19以内的数字}else if(n >= 20 && n <= 99 && n%10 == 0)     //整十{cout<<tens[n/10];}else if(n >= 20 && n <= 99)          //先输出十位,再输出个位{cout<<tens[n/10]<<" "<<table[n%10];}else if(n >= 100 && n<= 999){print(n/100);cout<<" "<<tens[10]<<" ";    //输出百位print(n%100);                //递归调用,输出十位和个位}else if(n >= 1000 && n <= 999999){print(n/1000);cout<<" "<<tens[11]<<" ";    //输出千位print(n%1000);               //递归调用,输出百位、十位和个位}}int main(void){int n;while(cin>>n){print(n);cout<<endl;}system("pause");return 0;}

运行效果图如下: